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3 years ago

In science, a force is a push or a pull. is it true or false ?

Engineering

1 answer:

AysviL [449]3 years ago

8 0

Answer:

true

Explanation:

because it is a external agency which Change or tends to change the state of rest or uniform motion in a straight line

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what do you expect the future trends of an operating system in terms of (a) cost (b) size (c) multitasking (d) portability (e) s

tino4ka555 [31]

Answer:

plz follow in titkok

Explanation:

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3 years ago

What are significant figures

lesantik [10]

Answer:

rounding

Explanation:

each of the digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit.

4 0

3 years ago

The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a contin

AlexFokin [52]

Answer: The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous rv X with the following

Explanation:

8 0

3 years ago

Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm an

ser-zykov [4K]

Answer:

volumetric flow rate = $0.0251 m^3/s$

Velocity in pipe section 1 = $6.513m/s$

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the volume will be mass/density

25/997 = $0.0251 m^3/s$

volumetric flow rate = $0.0251 m^3/s$

Average velocity calculations:

<em>Pipe section A:</em>

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s$

<em>Pipe section B:</em>

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s$

7 0

3 years ago

Discuss the impact of the changing urban center. Include the impacts on political, economic, and social roles and opportunities.

KengaRu [80]

Answer:

The 21st century world have been earmarked with great influx of people to the urban centre,the notion of gender equality and female education have also made most traditional roles in the family changing.Before now,wives we're known for their full independence on their husband who is considered the bread winner.

Inspite of the growth of of the urban centre the availability of resources have dwindled,resulting in the surge of unemployment in many urban centre,the political entity of the society which is the government have serious challenging in managing the various threat posed by overpopulation, unemployment results in the decrease of standard of living of person and family,to cater for this family have to change their roles,wives now work to support the husband.

Explanation:

6 0

3 years ago