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zepelin [54]
3 years ago
14

Please Help ASAP

Physics
1 answer:
asambeis [7]3 years ago
5 0

Answer:

A - a magnet is moving toward a wire loop

Explanation:

as the magnet moves towards the wire loop its flux increase which activates (or produces) the electric current.

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The potential energy of a particle as a function of position will be given as U(x) = A x2 + B x + C, where U will be in joules w
satela [25.4K]

Answer:

F = - 2 A x - B

Explanation:

The force and potential energy are related by the expression

      F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^

Where i ^, j ^, k ^ are the unit vectors on the x and z axis

The potential they give us is

     U (x) = A x² + B x + C

Let's calculate the derivatives

    dU / dx = A 2x + B + 0

The other derivatives are zero because the potential does not depend on these variables.

Let's calculate the strength

      F = - 2 A x - B

3 0
3 years ago
Which of the following supports the theory of continental drift?
Y_Kistochka [10]
I think it's The fossil record. The same animal fossil is in Africa and South America. The animal could have not swim across so its the fossil record
7 0
3 years ago
Because P and S waves travel faster through the Earth's mantle than through Earth's crust, scientists know that the mantle is __
larisa [96]
B. liquid and less denser
6 0
3 years ago
Read 2 more answers
Long ago, it was believed that maggots came from meat. In the late 1600s, Francesco Redi hypothesized that maggots came from fli
Lunna [17]
D) Both A and B.

Francisco Redi must use 1)a covered, unrefrigerated meat and 2) an uncovered, refrigerated meat to experiment and test his hypothesis that maggots came from flies rather than from meat.
5 0
3 years ago
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An electron is moving east in a uniform electric field of 1.55 N/C directed to the west. At point A, the velocity of the electro
valkas [14]

Answer:

Final velocity of electron, v=6.45\times 10^5\ m/s    

Explanation:

It is given that,

Electric field, E = 1.55 N/C

Initial velocity at point A, u=4.52\times 10^5\ m/s

We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

v^2=u^2+2as........(1)

a is the acceleration, a=\dfrac{F}{m}

We know that electric force, F = qE

a=\dfrac{qE}{m}

Use above equation in equation (1) as:

v^2=u^2+\dfrac{2qEs}{m}

v^2=(4.52\times 10^5\ m/s)^2+2\times \dfrac{1.6\times 10^{-19}\ C\times 1.55\ N/C}{9.1\times 10^{-31}\ kg}\times 0.395\ m

v = 647302.09 m/s

or

v=6.45\times 10^5\ m/s

So, the final velocity of the electron when it reaches point B is 6.45\times 10^5\ m/s. Hence, this is the required solution.

3 0
3 years ago
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