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LenKa [72]
3 years ago
9

1. A car travels a distance of 200 m in 4 seconds. What is the velocity of the car?

Physics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

velocity = distance / time taken

= 200/4

= 50 m/s

is the correct answer

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An electron moving with a velocity v= 5.0 × 107 m/s i enters a region of space where perpendicular electric and a magnetic field
liq [111]

Answer:

The magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

Explanation:

Given that,

Velocity of the electron, v=5\times 10^7\ m/s

Electric field, E=10^4\ V/m\ j

We need to find the magnetic field that will allow the electron to go through the region without being deflected. It can be calculated as :

qE=qvB\ \sin\theta

Here, \sin\theta=90^{\circ}

E=vB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{10^4}{5\times 10^7}\\\\B=2\times 10^{-4}\ T

So, the magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

6 0
3 years ago
A beam of light, initially travelling in the air, strikes water surface at an angle of 24.5° with the normal. If the speed of li
kykrilka [37]

Answer:

Explanation:

n = 3.00e8/2.22e8 = 1.35

1.00sin24.5 = 1.35sinθ

θ = 17.9°

8 0
3 years ago
10%) Problem 7: Water flows through a water hose at a rate of Q1 = 620 cm3/s, the diameter of the hose is d1 = 1.99 cm. A nozzle
Semenov [28]

Answer:

a) A_1 = \frac{\pi d_1^2}{4}

Explanation:

a) the cross-sectional area of the hose would be the square of radius times pi. And since the sectional radius is half of its diameter d. We can express the cross-sectional area A1 in term of diameter d1

A_1 = \pi r_1^2 = \pi (d_1/2)^2 = \frac{\pi d_1^2}{4}

6 0
3 years ago
II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

3 0
3 years ago
PLEASE HELP ASAP
otez555 [7]

Answer:

D: unconscious

Explanation:

Apex have a nice day :)

7 0
4 years ago
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