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LenKa [72]
3 years ago
9

1. A car travels a distance of 200 m in 4 seconds. What is the velocity of the car?

Physics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

velocity = distance / time taken

= 200/4

= 50 m/s

is the correct answer

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pogonyaev

Answer:

c

Explanation:

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2 years ago
For any string w = w1w2 · · · wn, the reverse of w, written w R, is the string w in reverse order, wn · · · w2w1. For any langua
Nata [24]

Answer:

Attached is a solution.

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An incredible amount of electrical energy passes down the funnel of a large tornado every second. Measurements taken in Oklahoma
Lorico [155]

Answer:

675 A

Explanation:

B = 1.5 x 10^-8 T

r = 9 km = 9000 m

Let the current be i

The formula for the magnetic filed due to a very long straight conductor is given by

B =\frac{\mu_{0}}{4\pi }\times \frac{2i}{r}

1.5\times 10^{-8} =10^{-7}\times \frac{2i}{9000}

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3 years ago
An oscillating block-spring system has a mechanical energyof 1.00 J and amplitude of 10.0 cm and a maximum speed of 1.20m/s. Fin
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Answer:

Explanation:

Given

Mechanical Energy of Spring-Block system is 1 J

Maximum Amplitude is A=10 cm

maximum speed v_{max}=1.2 m/s

Suppose x=A\sin \omega tbe general equation of motion of spring-mass system

where A=max amplitude

\omega=Natural frequency of oscillation

t=time

v_{max}=A\omega =1.2

0.1\cdot \omega =1.2

\omega =12 rad/s

maximum kinetic Energy must be equal to total Mechanical Energy when spring is un deformed i.e. at starting Position

\frac{1}{2}mv_{max}^2=1

m=\frac{2}{1.2^2}=\frac{2}{1.44}=1.38 kg

Also \omegais also given by

\omega =\sqrt{\frac{k}{m}}

k=\omega ^2\cdot m

where k= spring constant

k=12^2\cdot 1.38

k=200 N/m

             

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3 years ago
My heart strike him to dead.what figure of speech is that?​
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Hyperbole

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this is an extreme exaggeration or overstatement/ magnification

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