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Alecsey [184]
3 years ago
13

Muscles make up ore than __ of a person body?a.10b.25c40d.75

Physics
2 answers:
exis [7]3 years ago
8 0
40 percent of your body
Vsevolod [243]3 years ago
8 0
Yea it more then 40% C
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In the circuit shown, the galvanometer shows zero current. The value of resistance R is :
Tasya [4]

Answer:

its supposed to be (a) 1W

8 0
3 years ago
State ohm’s law Q.34.7
defon

Ohm's law states that: V=RI

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

V \propto I

where

V is the potential difference

I is the current

The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

V=RI

where R is the resistance. By rewriting the equation as

I=\frac{V}{R}

we see that the larger the resistance, the lower the current in the conductor.

Learn more about Ohm's law:

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4 0
3 years ago
Identify the number of neutrons in one atom of sulfur with an isotopic mass number of 34 amu.
Musya8 [376]
So, using the periodic table of elements, we know that the atomic number of sulfur is 16, which stands for the number of protons/electrons in the atom. Since the mass number, in this case is 34, is the sum of protons and neutrons, all we have to do is subtract 16 from 34, which will give us 18, the number of neutrons for this isotope of sulfur. :)
6 0
3 years ago
Read 2 more answers
Two point charges exert a 7.35 N force on each other. What will the force become if the distance between them is increased by a
I am Lyosha [343]

Answer :

New force becomes, F' = 1.83 N

Explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

q_1\ and\ q_2 are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

F'=\dfrac{kq^2}{r'^2}

F'=\dfrac{kq^2}{(2r)^2}

F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}

F'=\dfrac{1}{4}\times 7.35

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.          

3 0
3 years ago
Does anyone know the answer to this?
sweet-ann [11.9K]
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*

3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.

Please note that y:x relations are always straight lines while  relations are parabolic lines.

Hope this helps!
5 0
3 years ago
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