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vaieri [72.5K]
3 years ago
5

If 18.7 ml of 0.01500 Maqueous HCl is required to titrate 15.00 ml of an aqueous solution of NaOH to

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

The molarity of  NaOH is 0.02 M.

Explanation:

Given data:

Volume of HCl = 18.7 mL

Molarity of HCl = 0.01500 M

Volume of NaOH = 15.00 mL

Molarity of NaOH = ?

Solution:

M₁V₁  = M₂V₂

0.01500 M × 18.7 mL  = M₂ ×  15.00 mL

M₂ = 0.3 M.mL /15.00 mL

M₂ = 0.02 M

The molarity of  NaOH is 0.02 M.

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Suppose 11.4g of ammonium chloride is dissolved in 250 ml of a 0.3M aqueous solution of potassium carbonate. Calculate the final
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Answer:

The molarity of the final ammonium cation is 0.252M

Explanation:

<u>Step 1:</u> Data given

Mass of ammonium chloride (NH4Cl) = 11.4 grams

Volume of 0.3 M aqueous solution of potassium carbonate (K2CO3) = 250 mL = 0.250L

<u>Step 2:</u> The balanced equation

2NH4Cl + K2CO3 → 2KCl + (NH4)2CO3

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<u>Step 5:</u> Calculate moles (NH4)Cl at the equilibrium

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Molarity of NH4+ = 0.252 M

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If 45.0 mL of 0.25 M HCl is required to completely neutralize 25.0 mL of NH3, what is the concentration of the NH3 solution? Sho
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