Answer:
e) half
Explanation:
as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is
Q = CV ...........(i)
we also know capacitance of a capacitor for separation d and area A is
C = ∈₀A/d ...........(ii)
from the above equation it is clear that C is inversely proportional to separation if separation doubled capacitance will reduced to half and from equation first charge is directly proportional to capacitance.
that s why magnitude of charge will reduced to half
so option (e) is right answer
I think you get half of the magnetic field and that means half the power of the magnetic field.
To show motion on a graph you draw the path of where the object has gone
Answer:
Dinesh should put the fulcrum 2 m from himself and 7 m from the package.
Explanation:
Let the fulcrum be x meters from Dinesh's end.
The sum of clockwise moment must balance the sum of anti-clockwise moment.
Taking a moment about the fulcrum
(Force exerted by Dinesh) × (Distance of Dinesh from the fulcrum) = (Weight of the package) × (Distance of the package from the fulcrum)
Force exerted by Dinesh = 1127 N
Distance of Dinesh from the fulcrum = x m
Weight of the package = 322 N
Distance of the package from the fulcrum = (9 - x) m
1127 × x = 322 (9 - x)
1127x = 2,898 - 322x
1127x + 322x = 2,898
1449x = 2898
x = (2898/1449) = 2 m
Hence, Dinesh should put the fulcrum 2 m from himself and 7 m from the package.
Hope this Helps!!!
Answer:
mass of the other asteroid =
Explanation:
We use the definition for the force between two celestial objects under the action of the gravity they produce using newton's general gravitational constant:
The force between the two asteroids will then be given by:
where G is Newton's gravitational constant, the asterioid's masses are M1 and M2 respectively, and d is the distance between them.
We replace the known values in he equation above, and solve for the missing mass:
Since the units for the given quantities are all in the SI system, our resultant units for the unknown mass of the asteroid will be in kg.