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LiRa [457]
3 years ago
5

in the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will e produced from 75.0 milliliters of

a 1.0 M HCl in an excess of Mg?
Chemistry
1 answer:
Anna35 [415]3 years ago
6 0
This question uses mole ratios. firstly, we look at how many moles of H2 are produced for every mole of HCl: from 1 Hcl, we get half a mole of H2. therefore, however many moles of HCl are present in the 0.075 L of 1.0M HCl, half that number of H2 moles will be produced. 

n=cv
  =0.0750 x 1.0
  =0.075 mol HCl
n(H2)= 0.5 x n(HCl)
         =0.0375 moles of H2
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(2) The value of equilibrium constant for this reaction is, 8.77

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The given chemical equation is:

2NO(g)+Br_2(g)\rightarrow 2NOBr(g)

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We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

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The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

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(2) NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

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