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Ksivusya [100]
3 years ago
15

A 2-kg bowling ball is 1 meter off the ground on a post when it falls just before it reaches the ground it is traveling 4.4m/s a

ssuming that there is no air resistance witch statement is true
A) the mechanical energy is conserved
B) the initial potential energy is less then the final kinetic energy
C) the mechanical energy is not conserved
D) the initial potential energy is greater then the final kinetic energy
Physics
2 answers:
Galina-37 [17]3 years ago
8 0

Your answer will be A) The mechanical energy is conserved (:

marta [7]3 years ago
4 0
Mechanical energy is conserved
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The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t>0 , where is measured in seconds and
8090 [49]

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at 0.

The total distance traveled in the first 10 seconds is 847 m.

<h3>When is a particle at rest?</h3>
  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s

The velocity is positive at when the time of motion is as follows;

0.

The total distance traveled in the first 10 seconds is calculated as follows;

2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m

Learn more about motion of particles here: brainly.com/question/11066673

4 0
2 years ago
Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en
konstantin123 [22]

Explanation:

(a) Frequency of radar energy, f = 10\ GHz =10^{10}\ Hz

The relation between frequency and wavelength is given by :

c=f\lambda

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8}{10^{10}}

\lambda=0.03\ m

or

\lambda=3\ cm

(b) If wavelength, \lambda=25\ cm=0.25\ m

c=f\lambda

f=\dfrac{c}{\lambda}

f=\dfrac{3\times 10^8}{0.25}

f=1.2\times 10^9\ Hz

or

f = 1.2 GHz

Hence, this is the required solution.

7 0
3 years ago
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