Ask question

Ask question

All categories

3 years ago

15

A 2-kg bowling ball is 1 meter off the ground on a post when it falls just before it reaches the ground it is traveling 4.4m/s a

ssuming that there is no air resistance witch statement is true
A) the mechanical energy is conserved
B) the initial potential energy is less then the final kinetic energy
C) the mechanical energy is not conserved
D) the initial potential energy is greater then the final kinetic energy

2 answers:

Galina-37 [17]3 years ago

8 0

Your answer will be A) The mechanical energy is conserved (:

marta [7]3 years ago

4 0

Mechanical energy is conserved

You might be interested in

Suppose the ends of a 27-m-long steel beam are rigidly clamped at 0°C to prevent expansion. The rail has a cross-sectional area

frozen [14]

Answer:

F = 1.58*10^{11} N

Explanation:

given data:

length of steel beam = 27 m

cross sectional area of rail = 35 cm

$\Delta T = 39$ Degree celcius

change in length of steel beam is given as

$\Delta L = L_O \alpha \Delta T$

$= 20*1.1*10^{-5}*39$

$=8.58*10^{-3}$ m

Young's modulus is

$Y = \frac{FL}{A\Delta L}$

$F = \frac{ YA\Delta L}{L}$

$= \frac{2.0*10^{11}*25*10^{-4}8.58*10^{-3}}{27}$

F = 1.58*10^{11} N

5 0

3 years ago

Usually, tall trees collapse in stroms?<br>

sergey [27]

Taller trees are more likely to fall during storms than short trees.

3 0

3 years ago

Read 2 more answers

In which activities is speed helpful? Running track Swimming Riding in a bike race All of the above

Burka [1]

Answer:

all of the above

Explanation:

they all require speed to beat

6 0

2 years ago

Read 2 more answers

How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?

Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction $\mu _k=0.10$

Initial speed $u=3.9\ m/s$

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

$a_{max}=\mu _k\cdot g$

$a_{max}=0.1\times 3.9=0.39\ m/s^2$

using equation of motion

$v^2-u^2=2 as$

where $v=final\ velocity$

$u=initial velocity$

$a=acceleration$

$s=displacement$

$(0)-(3.9)^2=2\times (-0.39)\times s$

$s=19.5\ m$

6 0

3 years ago

Your bedroom has a rectangular shape and you want to measure its size. You use a tape that is precise to 0.001 m and find that t

Alex73 [517]

Your bedroom has a rectangular shape, and you want to measure its area. You use a tape that is precise to 0.001 and find that the shortest wall in the room is 3.547 long. The tape, however, is too short to measure the length of the second wall, so you use a second tape, which is longer but only precise to 0.01 . You measure the second wall to be 4.79 long. Which of the following numbers is the most precise estimate that you can obtain from your measurements for the area of your bedroom?

b)If your bedroom has a circular shape, and its diameter measured 6.32 , which of the following numbers would be the most precise value for its area?

a)30 m^2

b) 31.4 m^2

c)31.37 m^2

d)31.371 m^2

Answer:

Part A

$A = 16.99 \ m^2$

Part B

$A_r =31.37 \ m^2$

Explanation:

From the question we are told that

The shortest wall is $x = 3.547 \ m$

The length of the second wall is $y = 4.79 \ m$

Generally the area is mathematically evaluated as

$A = x * y$

=> $A = 3.547 * 4.79$

=> $A = 16.99 \ m^2$

Given that the diameter is d = 6.32

Then the area is

$A_r = \pi \frac{d^2}{4}$

$A_r =3.142 * \frac{6.32^2}{4}$

$A_r =31.37 \ m^2$

3 0

3 years ago