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3 years ago

molybdenum, MO, forms a chloride with the formula MoCl6. what is the most probable formula for its oxide?

Chemistry

1 answer:

Andru [333]3 years ago

4 0

Mo₂O₆

Explanation:

The probable formula of its oxide is Mo₂O₆ in combined form.

The formula MoCl₆ gives us insight about the combining power of element Mo;

To form MoCl₆;

Mo Cl

Combining

power 6 1

Exchange 1 6

Compound MoCl₆

Now we know that the combining power of Mo is 6

Using the periodic table, we know that the combining power of oxygen is 2

Combining powers of an atom is the number of electrons is gains, shares or loses during a chemical combination:

Mo O

Combining

power 6 2

Exchange 2 6

Compound Mo₂O₆

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Compound brainly.com/question/10216585

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Part IV. Limiting Reactants! A Challenge Problem!

Alexxandr [17]

Answer:

a. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

b. Fe2O3 is the limiting reactant.

c. 6.30 grams Fe

d. 52.6 %

Explanation:

Step 1: Data given

Mass of iron(III) oxide Fe2O3 = 9.00 grams

Mass of aluminium = 4.00 grams

Molar mass Fe2O3 = 159.69 g/mol

Aluminium molar mass = 26.98 g/mol

Step 2: The balanced equation

Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

Step 3; Calculate Moles

Moles = mass / molar mass

Moles Fe2O3 = 9.00 grams / 159.69 g/mol

Moles Fe2O3 = 0.0564 moles

Moles Al = 4.00 grams / 26.98 g/mol

Moles Al = 0.148 moles

Step 4: Calculate limiting reactant

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

Fe2O3 is the limiting reactant. It will completely be consumed (0.0564 moles). Al is in excess. There will react 0.0564*2 = 0.1128 moles

There will remain 0.148 - 0.1128 = 0.0352 moles Al

Step 5: Calculate moles Fe

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

For 0.0564 moles Fe2O3 we'll have 2*0.0564 = 0.1128 moles Fe

Step 6: Mass of Fe

Mass Fe = 0.1128 moles * 55.845 g/mol

Mass Fe = 6.30 grams

Step 7: If you carried out this reaction and it actually produced 0.475 mL of molten iron (r = 6.98 g/mL), what is the percent yield of this reaction?

Density = mass / volume

Mass = density * volume

Mass = 6.98 g/mL * 0.475 mL

Mass = 3.3155 grams

Percent yield = (actual mass / theoretical mass) * 100%

Percent yield = (3.3155 /6.30 ) * 100 %

Percent yield = 52.6 %

3 0

3 years ago

In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant

BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

In another experiment, if 80 $XO_3$ molecules react with 104 $BrZ_3$ molecules. How many $Br_2$ molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of $BrZ_3$ react with 6 molecule of $XO_3$

So, 104 molecules of $BrZ_3$ react with $\frac{104}{8}\times 6=78$ molecule of $XO_3$

From this we conclude that, $XO_3$ is an excess reagent because the given moles are greater than the required moles and $BrZ_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of $Br_2$

From the reaction, we conclude that

As, 8 molecules of $BrZ_3$ react to give 4 molecules of $Br_2$

So, 104 molecules of $BrZ_3$ react to give $\frac{104}{8}\times 4=52$ molecules of $Br_2$

Hence, the number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

4 0

3 years ago

A balloon contains a 10% glucose solution. The balloon is permeable to water but not to glucose. A beaker contains a 5% glucose

deff fn [24]

The state of the balloon:

When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.

What is Osmosis:

Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.

Hypertonic solution:

It means that there are more solutes present in the surrounding environment than in the cell itself.

Hypotonic solution:

In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.

When comparing two solutions, the one with the larger solute concentration is hypertonic, and the one with the lower solute concentration is hypotonic. Isotonic solutions have an identical solute concentration.

While the solution in the beaker is hypertonic, Meaning that will draw water molecules out of the cell. As water molecules move from a location of high water potential (dilute solution) to a region of reduced water potential (10% glucose solution), the water from the 5% glucose solution will flow into the 10% one (concentrated solution)
This is the reason why the amount of water decreases when the balloon is submerged in the beaker.

Learn more about the glucose solution and permeability here,

brainly.com/question/14748422

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7 0

2 years ago

What is minimum volume of oxygen required to react with 42.5 g of aluminum in the synthesis of aluminum oxide at stp?

natka813 [3]

26.833 liters

Aluminum oxide has a formula of Al₂O₃, which means for every mole of aluminum used, 1.5 moles of oxygen is required (3/2 = 1.5).

Given 42.5 g of aluminum divided by its atomic mass (26.9815385) gives 1.575 moles of aluminum.

Since it takes 1.5 moles of oxygen per mole of aluminum to make aluminum oxide, you'll need 2.363 moles of oxygen atoms.

Each molecule of oxygen gas has 2 oxygen atoms, so the moles of oxygen gas will be 2.363/2 = 1.1815

Finally, you need to calculate the volume of 1.1815 moles of oxygen gas.
1 mole of gas at STP occupies 22.7 liters of volume. Therefore,

1.1815 * 22.7 = 26.8 liters of oxygen gas.

6 0

4 years ago

A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor

Valentin [98]

According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808
when we assume the moles of solute NaCl = X
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
So X (the no.of moles of NaCl) = 0.027 m

8 0

3 years ago