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Ber [7]
3 years ago
15

In common speech, some people may use the terms hypothesis and theory interchangeably. In science, however, the terms have diffe

rent meanings. What do you think is an important difference between a hypothesis and a theory?
Chemistry
2 answers:
kari74 [83]3 years ago
8 0

Answer: In science, a hypothesis is a possible explanation for an observation, while a theory is an explanation that is supported by a large body of evidence.

Explanation: exact answer

Leto [7]3 years ago
3 0

Answer:

A hypothesis is something you can test a theory is just a thought that you have.

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Complete the following chart to fill in the blanks
raketka [301]
Im so sorry i don’t know I just need to answer 2 questions for me to be Able to ask
7 0
3 years ago
When one thing in a _____ circuit stops working, the whole circuit stops working.
scZoUnD [109]

Answer: When one thing in a <u>electric</u> circuit stops working, the whole circuit stops working.

Explanation:

8 0
3 years ago
Read 2 more answers
It takes 281.7 kJ of energy to remove 1 mole of electrons from the atoms on the surface of lithium metal. If lithium metal is ir
Alex17521 [72]

Answer:

The maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

Explanation:

We know that total energy

E = \frac{hc}{\lambda}  ------------ (1)

Here h = plank's constant = 6.62 × 10^{-34} J s

c = speed of light = 3 × 10^{8} \frac{m}{s}

\lambda = 261 nm = 261  × 10^{-9} m

Put all these values in equation (1) we get

E = 7.6   × 10^{-19} J

We know that

Total energy = Energy to remove an electron + K.E of electron

Energy to remove an electron = \frac{281.7 (1000)}{(6.023)10^{23} }

Energy to remove an electron = 4.67  × 10^{-19} J

K.E of electron = Total energy - Energy to remove an electron

K.E of electron = 7.6   × 10^{-19} -  4.67  × 10^{-19}

K.E of electron = 2.93 × 10^{-19} Joule

Therefore the maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

3 0
4 years ago
Consider these two entries from a fictional table of standard reduction potentials.
Vika [28.1K]

Answer:

1.89 V

Explanation:

To calculate the standard cell potential, subtract the reduction potential of the anode from the reduction potential of the cathode.

So for your calculation,

-0.22 V - (-2.11 V)= 1.89 V

8 0
3 years ago
What is the maximum number of grams of copper that could be produced by the reaction of 30.0 of copper oxide with excess methane
Solnce55 [7]

Answer: 24.13 g Cu

Explanation:

<u>Given for this question:</u>

M of CuO = 30 g

m of CuO = 79.5 g/mol

Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol

= 0.38 mol

The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:

CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)

The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side

4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)          

From the stoichiometry of the balanced equation:

4 moles of CuO gives 4 moles of Cu

1 mole of CuO gives 1 mol of Cu

0.38 mol of CuO gives 0.38 mol of Cu

Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu

= 0.38 × 63.5 g

= 24.13 grams        

Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane                                        

4 0
2 years ago
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