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Elis [28]
4 years ago
6

We cannot consider something to be work unless

Physics
2 answers:
bogdanovich [222]4 years ago
8 0

Answer:

When displacement caused by force is zero or force is perpendicular to displacement then we consider there will be no work done

Explanation:

We know that work done is given by W=Fdcos\Theta, here F is force applied and d is the displacement caused by the force

Now there are two case in which work done will be zero that is, either displacement is zero or \Theta =90^{\circ} that is force and displacement are perpendicular to each other

So when displacement caused by force is zero or force is perpendicular to displacement then we consider there will be no work done

Alla [95]4 years ago
4 0
We cannot consider something to be work unless <span>force applied causes movement of an object in the same direction as the applied force. </span>
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A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0
Helen [10]

Answer:

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv   m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

6 0
3 years ago
1. A perspex box has a 10 cm square base and contains water to a height of 10 cm. A piece of rock of mass 600g is lowered into t
AnnZ [28]

Answer:

(a) The volume of water is 100 cm³

(b) The volume of the rock is 20 cm³

(c) The density of the rock is 30 g/cm³

Explanation:

The given parameters of the perspex box are;

The area of the base of the box, A = 10 cm²

The initial level of water in the box, h₁ = 10 cm

The mass of the rock placed in the box, m = 600 g

The final level of water in the box, h₂ = 12 cm

(a) The volume of water in the box, 'V', is given as follows;

V = A × h₁

∴ The volume of water in the box, V = 10 cm² × 10 cm = 100 cm³

The volume of water in the box, V = 100 cm³

(b) When the rock is placed in the box the total volume, V_T, is given by the sum of the rock, V_r, and the  water, V, is given as follows;

V_T = V_r + V

V_T = A × h₂

∴ V_T = 10 cm² × 12 cm = 120 cm³

The total volume, V_T = 120 cm³

The volume of the rock, V_r = V_T - V

∴ V_r = 120 cm³ - 100 cm³ = 20 cm³

The volume of the rock, V_r = 20 cm³

(c) The density of the rock, ρ = (Mass of the rock, m)/(The volume of the rock)

∴ The density of the rock, ρ = 600 g/(20 cm³) = 30 g/cm³

8 0
3 years ago
A 42-kg crate rests on a horizontal floor, and a 52-kg person is standing on the crate. (a) determine the magnitude of the norma
Lemur [1.5K]
Hope this helps you.

6 0
3 years ago
Which is the Colour of cleanliness
kirill [66]
White is the cleanliness color
3 0
3 years ago
How far (in meters) above the earth's surface will the acceleration of gravity be 21.0 % of what it is on the surface?
weeeeeb [17]

Answer:

7532m

Explanation:

Gravity on the surface of the earth with radius R is given by:

F_1=\frac{Gm_{earth}m_{object}}{R^2_{earth}}

Gravity a distance r above the surface:

F_2=\frac{Gm_{earth}m_{object}}{(R+r)^2}

How big is r if:

F_2=0.21\times F_1

You get the following equation:

R^2=0.21(R+r)^2=0.21R^2+0.41Rr+0.21r^2

Solve for r:

r^2+2Rr-\frac{79}{21} R^2=0

r=-R+\sqrt{R^2+\frac{79}{21}R^2}=-R+\sqrt{\frac{100}{21}R^2}=(\frac{10}{\sqrt{21}}-1)R

8 0
3 years ago
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