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agasfer [191]
3 years ago
6

Two small insulating spheres with radius 9.00*10^-2m are separated by a large center-to-center distance of 0.520m . One sphere i

s negatively charged, with net charge -2.40uC , and the other sphere is positively charged, with net charge 3.35uC . The charge is uniformly distributed within the volume of each sphere.
a)

What is the magnitude E of the electric field midway between the spheres?

Take the permittivity of free space to be ?0 = 8.85
Physics
1 answer:
Ganezh [65]3 years ago
5 0

British realized their northern strategy had failed

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12. A las 10 de la mañana Elena sale a 100 Km/h de una ciudad A con dirección a Madrid. A la misma hora sale Javier desde otra c
Klio2033 [76]

Answer:

a) t = 3.3 [h]

b ) Hora = 13:18 o 1:18 [pm]

c) x = 327.79 [km/h] (Elena)

x = 196.6 [km] (Javier)

Explanation:

Para poder solucionar este problema debemos hacer un planteamiento inicial de ubicacion de las ciudades, este planteamiento nos ayudara a entender el problema de una manera mas facil.

Tenemos las ciudades A & B y la ciudad de Madrid que esta a una distancia x con respecto de B, (ver esquema adjunto).

De manera logica debemos deducir que la Ciudad A debe estar mas lejos de Madrid que la ciudad B de la misma Madrid, ya que en caso contrario Javier nunca alcanzara a Elena, ya que Elena va mas rapido que Javier.

a) Ahora debemos de utilizar la siguiene ecuacion de la cinematica, cuando los cuerpos se mueven a velocidad constante.

x=x_{o}+v*t

Donde:

x -xo = Distancia entre el punto inicial y punto final.

v = velocidad [m/s]

t = tiempo [s]

Debemos convertir las velocidades de kilometros por hora a metros por segundo.

100 [\frac{km}{h} ]*1[\frac{h}{3600s}]*1000[\frac{m}{1km} ] = 27.77[m/s]\\60[\frac{km}{h} ]*1[\frac{h}{3600s}]*1000[\frac{m}{1km} ] = 16.66[m/s]

Seguidamente formulamos una ecuacion por cada movimiento, luego debemos igualar estas ecuaciones en funcion de la variable x que sera el punto donde se encuentren ambas personas.

<u>Para Elena</u>

(132000+x) = 27.77*t\\x = 27.77*t - 132000

<u>Para Javier</u>

<u />x - xo = 16.66*t\\xo = 0\\x = 16.66*t<u />

Igualamos las variables x de ambas ecuaciones.

16.66*t = 27.77*t -132000\\27.77*t - 16.66*t = 132000\\11.11*t = 132000\\t = 11880.83 [s] = 3.3 [h]

b) La hora facilmente se puede encontrar sumando el tiempo con las 10:00am

hora = 10 + 3 = 13 [hrs]

La parte decimal debe convertirse a tiempo.

0.3 [hr]*60[\frac{min}{1hr} ]= 18 min

Hora = 13:18 o 1:18 [pm]

c) Para encontrar estas distancias utilizamos el tiempo encontrado en el item a.

<u>Para Elena</u>

x = v*t\\x = 27.77*11800.83 = 327791.6 [m] = 327.79 [km]\\

<u>Para Javier</u>

<u />x = v*t\\x = 16.66*11800.83 = 196601.8 [m] = 196.6 [km]<u />

6 0
3 years ago
What are the primary functions of
ycow [4]

C.Provide Structural Support.

hope this helps.

7 0
3 years ago
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Why in the absence of air do all objects fall at the same rate?
geniusboy [140]

Answer:

objects falling at same rate.

Explanation:

ifif you neglect air resistance, objects following your Earth's surface or with the same approximate acceleration 9.8 meters per second squared (9.8 m/s^2, or g) due to Earth's gravity.

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In this system, solar energy from sunlight causes the solar panel to create solar energy which flows into the incandescent light bulb. In the light buld, the solar energy is transformed into two different types of energy: light energy and electric energy.
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How do you calculate centripetal acceleration?
Delvig [45]

A particle has centripetal acceleration whenever it's a making a turn of radius R. If the particle is moving at a constant tangential speed v throughout the turn, then the magnitude of centripetal acceleration is

v²/R

If the particle is following a uniformly circular path, then it moves in a circle of radius R and travels a distance equal to its circumference, 2πR. Let T be the time it takes to complete one such loop. Then the entire circle is traversed with speed v = 2πR/T, so that the centripetal acceleration is also given by

v²/R = (2πR/T)²/R = 4π²R/T²

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2 years ago
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