Vi = 15 m/s
t = 2 s
a = 9.8 m/s^2
y = ?
The kinematic equation that has all of our variables is d = Vi*t + 0.5*a*t^2
y = 15*2 + 0.5*9.8*2^2 = 49.6 m
Answer:to transfer electric current from one point to another
Explanation:
To transfer electric current from one point to another
M = 7.0 kg, the mass of the groceries
h = 1.2 m, the elevation of the bag of groceries
The bag of groceries moves a constant velocity over the 2.7-m room.
At constant velocity, there is no applied force, and the kinetic energy remains constant.
At an elevation of 1.2 m, there is an increase in PE (potential energy) given by
V = m*g*h
= (7.0 kg)*(9.8 m/s²)*(1.2 m)
= 82.32 J
The change in PE is equal to the work done.
Answer: 82.3 J
Answer:
The object distance is 92 cm.
Explanation:
let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.
then, the magification of the mirror is given by:
m = -v/u and m = h/H
so, -v/u = h/H
u = -v×H/h
= -(-4.6)×(82)/(4.1)
= 92 cm
Therefore, the object distance is 92 cm.
