Answer:

Explanation:
Molarity refers to a measure of concentration.
Molarity = moles of solute/Litres of solution
Molarity refers to number of moles of solute present in this solution.
In order to find a solution's molarity, use value for the number of moles of solute and the total volume of the solution expressed in liters
As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,
Molarity = 
The answers that apply include;
- A saturated fatty acid with a greater molar mass has a higher melting point than a saturated fatty acid with a low molar mass
- A saturated fatty acid has a higher melting point than an unsaturated fatty acid
Saturated acids do not have double bonds in their hydrocarbon tails. Therefore, because there are no kinks in the chains, the chains are well compacted due to numerous hydrogen bonds between each. The larger the chains (directly proportional to molar mass), the higher the melting point of these fats.
There’s no choices to pick from
About 0.92 kg of benzyl salicylate would be needed in order to manufacture 325 tubes of sunscreen.
A tube contains 4.0 oz of the sunscreen and each one 2.5% benzyl salicylate.
2.5% of 4.0 oz = 0.1 oz
Thus, each tube would need 0.1 oz of benzyl salicylate.
325 tubes of the sunscreen is needed and each one requires 0.1 oz of benzyl salicylate. Hence, total amount of benzyl salicylate needed would be:
325 x 0.1 oz = 32.5 oz
From conversion:
16 oz = 1 lb
Hence,
32.5 oz = 32.5/16
= 2.03 lb
Also:
2.205 lb = 1 kg
2.03 lb = 2.03/2.205
= 0.92 kg
More on dimensional analysis can be found here: brainly.com/question/22015862
Leftover: approximately 11.73 g of sulfuric acid.
<h3>Explanation</h3>
Which reactant is <em>in excess</em>?
The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a result,
- Al(OH)₃ is the limiting reactant.
- H₂SO₄ is in excess.
How many <em>moles</em> of H₂SO₄ is consumed?
Balanced equation:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.
How many <em>grams</em> of H₂SO₄ is consumed?
The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.
How many <em>grams</em> of H₂SO₄ is in excess?
40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.