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BabaBlast [244]
2 years ago
11

Write one common thing between condensation and hydrolysis ?​

Chemistry
1 answer:
serious [3.7K]2 years ago
8 0

Answer:

The common thing is the compound water

Explanation:

in condensation h2O is expelled while in hydrolysis water is used or added

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A Brønsted-Lowry acid Question 9 options: A) has a lower pH than vinegar. B) is any species that donates a proton. C) is any spe
rusak2 [61]

Answer:

B) is any species that donates a proton.

7 0
3 years ago
Write a chemical equation of Dr. Jeff’s demonstration using a battery to light steel wool on fire. The battery is used to allow
Elis [28]

Answer:

2Fe(s) + 3O2(g) --------> 2FeO3(s)

Explanation:

According to the question, a  battery was used  to light the steel wool by bringing the terminals very close together. When  the battery came into contact with the steel wool, current was sent out through the thin wire.  This caused the iron to heat up quite well.

Iron reacts with oxygen under these conditions as follows;

2Fe(s) + 3O2(g) --------> 2FeO3(s)

This is the chemical reaction that occurs when the steel wool is set on fire.

6 0
2 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
N2 + 3 H2 – 2 NH3 How many moles of nitrogen (N2) are required to get 6
Iteru [2.4K]

Answer:

N2 + 3H2 → 2NH3. 14 moles a. If 6 mol of H2 are consumed, how many moles of NH3 are produced? ... a 3 mol H₂. 4. How many moles of nitrogen are needed to make 11 moles of NH3? Il mol NH₃ x Imol Na = 15.5

5 0
3 years ago
Based on what you know about matter explain why the food coloring mixes at different rates
emmasim [6.3K]

Answer:

Matter has different densities. Different food colorings have different densities. Those with a higher density will sink to the bottom and mix much easier than one with a lower density. The higher density also contains more particles making it easier to mix or give it a fuller color.

3 0
2 years ago
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