Answer:
if Y is the position and X the time: in the first one you will see a crescent function that starts sharp and starts to curve down as the time pases. as the cart is slowing down, you will need more time to move the same as before.
Y (position)
I
sensor-------------------------------------------------------------------
I o
I o
I o
I o
I o
I o
I o
I------------------------------------------------------------------------------------- X (time)
in the second case the cart starts close to the sensor and starts getting sharper and sharper as the time pases. This is because the velocity is increasing, so for each second that pases, you will travel more distance that the second before it.
Y (position)
I
sensor ----------------------
I o
I o
I o
I o
I o
I o
I o
I------------------------------------------------------------------------------------- X (time)
i hope you can understand it, kinda hard to do graphs here.
Answer:
The sun
Explanation:
if they get too close even the heat that radiates of of it would burn you or give sunburn bad and the sun is a shining ball of energy it is way to hot for a human to get close
Are you referring to try to get into a college? if you are here is a basic outlay...
Your Street Address
City, State, Zip Code
Date
Name of Person, Title
Company/Organization
Street Address
City, State, Zip Code
Dear Mr./Ms./Dr. :
Introduction: State your reason for writing. Name the specific position or type of work for which you are applying. (Mention how you heard about the opening, if appropriate.)
Body: Explain why you are interested in working for that employer, or in that field of work, and what your qualifications are. Highlight two to three achievements that relate to the position and field. Refer the reader to the enclosed resume, application, and/or portfolio.
Closing: Thank the reader for his or her time and consideration. Indicate your desire for an interview and provide your contact information. If the employer is willing to accept phone calls, state that you will call to discuss the possibility of scheduling an interview.
Sincerely,
Your Name
<span>Enclosure / Attachment
</span>
Answer:
Explanation:
q = 2e = 3.2 x 10^-19 C
mass, m = 6.68 x 10^-27 kg
Kinetic energy, K = 22 MeV
Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A
(a) time, t = 2.8 s
Let N be the alpha particles strike the surface.
N x 2e = q
N x 3.2 x 10^-19 = i t
N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8
N = 2.36 x 10^12
(b) Length, L = 16 cm = 0.16 m
Let N be the alpha particles
K = 0.5 x mv²
22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²
v² = 1.054 x 10^15
v = 3.25 x 10^7 m/s
So, N x 2e = i x t
N x 2e = i x L / v
N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)
N = 4153.85
(c) Us ethe conservation of energy
Kinetic energy = Potential energy
K = q x V
22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V
V = 1.17 x 10^7 V
Answer:
Approximately 
.
Explanation:
<h3>Solve this question with a speed-time plot</h3>
The skateboarder started with an initial speed of 
and came to a stop when her speed became 
. How much time would that take if her acceleration is 
?
.
Refer to the speed-time graph in the diagram attached. This diagram shows the velocity-time plot of this skateboarder between the time she reached the incline and the time when she came to a stop. This plot, along with the vertical speed axis and the horizontal time axis, form a triangle. The area of this triangle should be equal to the distance that the skateboarder travelled while she was moving up this incline until she came to a stop. For this particular question, that area is approximately equal to:
.
In other words, the skateboarder travelled 
up the slope until she came to a stop.
<h3>Solve this question with an SUVAT equation</h3>
A more general equation for this kind of motion is:
,
where:
and 
are the initial and final velocity of the object,
is the constant acceleration that changed the velocity of this object from to , and
is the distance that this object travelled while its velocity changed from to .
For the skateboarder in this question:
.
