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harkovskaia [24]
2 years ago
8

A circuit has 3 resistors, all connected in parallel. Let R1 = 4.0 Ω, R2 = 3.0 Ω, and R3 = 6.0 Ω. What is the equivalent resista

nce of the circuit? Show all work and include units of measure.
Physics
2 answers:
ExtremeBDS [4]2 years ago
6 0

The effective resistance is the reciprocal of

1/4 + 1/3 + 1/6 =

3/12 + 4/12 + 2/12 =

9/12 Siemens

The reciprocal is 12/9 ohms.

That's 4/3 or 1.333 ohms.

Finger [1]2 years ago
5 0

Answer:

1 1/3 or 1.33333

Explanation:

First of all, you should note that the answer will be smaller than the smallest resistor. That means that the answer should be less than 3. Let's see if it is.

1/R1 + 1/R2 + 1/R3 = 1/Rt

  • R1 = 4
  • R2 = 3
  • R3 = 6

All resistors are in ohms.

1/4 + 1/3 + 1/6 = 1/Rt   You could do this using decimals, but the usual way is to use fractions.

The Common Denominator is 12

3/12 + 4/12 + 2/12 = 1/Rt

9/12 = 1/Rt                           Turn 9/12 upside down

12/9 = Rt

1 3/9 = RT

1 1/3 = Rt

1.3333 = Rt

The answer is under 3 so we know it should be right.

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mihalych1998 [28]
<span>We can use Coulomb's law to find the force F acting on the proton that is released. F = k x Q1 x Q2 / r^2 k = 9 x 10^9 Q1 is the charge on one proton which is 1.6 x 10^{-19} C Q2 is the same charge on the other proton r is the distance between the protons F = (9x10^9) x (1.6 x 10^{-19} C) x (1.6 x 10^{-19} C) / (10^{-3})^2 F = 2.304 x 10^{-22} N We can use the force to find the acceleration. F = ma a = F / m a = (2.304 x 10^{-22} N) / (1.67 x 10^{-27} kg) a = 1.38 x 10^5 m/s^2 The initial acceleration of the proton is 1.38 x 10^5 m/s^2</span>
8 0
3 years ago
Does Radiation Affects this question? If it doesn't, is the answer C?​
kotegsom [21]
The answer will be C
5 0
3 years ago
Assuming the diode is ideal but with a forward voltage drop of. 65 volts, what is the current in ma if v1=0v, and r1=490ω?
weeeeeb [17]

The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.

To find the answer, we have to know more about the ideal diode.

<h3>What is an ideal diode?</h3>
  • A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
  • A semiconductor diode is the kind of diode that is used the most commonly.
  • It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
<h3>How to find the current in ideal diode?</h3>
  • Here we have given with the values,

                       V_2=65V\\V_1=0V\\R_1=490Ohm.

  • We have the expression for current in mA of the ideal diode with forward biased voltage drop as,

                I=\frac{V_2-V_1}{R_1} =\frac{65}{490} =132.6mA

Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.

Learn more about the ideal diode here:

brainly.com/question/14988926

#SPJ4

7 0
1 year ago
Here we will calculate the work per unit charge on an electron moving between two potentials. A 9.0 V battery is connected acros
Svet_ta [14]

Answer:

2000 V/m

1778021.69323 m/s

Explanation:

V = Voltage = 9 V = \Delta V

q = Charge of proton = 1.6\times 10^{-19}\ C

m = Mass of electron = 9.11\times 10^{-31}\ kg

v = Velocity of electron

Electric field is given by

E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{9}{4.5\times 10^{-3}}\\\Rightarrow E=2000\ V/m

The electric field is 2000 V/m

Here, the energy of the system is conserved

\dfrac{1}{2}mv^2=q\Delta V\\\Rightarrow v=\sqrt{\dfrac{2q\Delta V}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 9}{9.11\times 10^{-31}}}\\\Rightarrow v=1778021.69323\ m/s

The velocity of the electron is 1778021.69323 m/s

4 0
3 years ago
A student builds an electromagnet using a battery, an iron nail, and some insulated wire. The wire is wrapped around the nail 50
dedylja [7]

Answer:

a

Explanation:

its right

5 0
3 years ago
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