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3 years ago

PLS HELP THIS IS DUE TODAY!!!!!!!!!

Physics

1 answer:

Juli2301 [7.4K]3 years ago

3 0

The speed at which the objects were attracted to each other determined by the gravitational pull.

<h3>What is gravity?</h3>

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity or gravitational pull.

The gravitational force, Fg is the attractive force exerted by the Earth on the object that is equal to the mass of the object times the gravitational acceleration.

When the two objects are attracted, the speed with which they are moving toward each other depends on the strength of the pull force. This pull force is the gravitational pull.

Thus, the speed at which the objects were attracted to each other determined by the gravitational pull.

Learn more about gravity.

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How does the launch angle affect the maximum height reached by a ground launched projectile?

NISA [10]

Answer:

The maximum height is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the maximum height.

Explanation:

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3 years ago

When is a white dwarf formed?

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When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf

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3 years ago

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Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t

alexandr1967 [171]

Answer:

a) the one with a lower orbit b) the one with a higher orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

$\frac{v^2}{r} = \frac{GM}{r^2}$ .

so the velocity is

$v = \sqrt{\frac{GM}{r} }$

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

$T = 2\pi \sqrt{\frac{a^3}{GM} }$

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0

4 years ago

How did people measure speed before speedometers and radar guns were invented

s344n2d4d5 [400]

Distance divided by time.

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3 years ago

You are driving at 25 m/s with your cruise control on when you see a fallen tree in the road. It takes you 0.30 s to put on the

xxTIMURxx [149]

Explanation:

Given data

velocity v= 25m/s

The time it takes to put on brake t= 0.3s

the distance covered when the brake was put on is

v=s/t

s= v*t

s= 25*0.3s

s= 7.5m

hence the distance covered is 7.5m

Also the rate of decrease in aceleration is 5m/s^2

we can also calculate the distance covered at this rate

v^2=u^2+2as

25^2= 0+2*5*s

625=10s

divide both sides by 10

s=625/10

s= 62.5m

The total distance covered between putting on the brakes and decelareation is 7.5+62.5= 70m

Given that the tree is 75m ahead, the car would not hit the tree

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3 years ago