It's velocity when it strikes the ground is. D. 232.9 kg.m/s<span>.
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I hope this helps!!!
Explanation:
Hey, there!
The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
Explanation:
change in the volume of the gas = 5.55 - 1.22
= 4.33 X 10⁻³ m³
external pressure ( constant ) P = 1 x 10⁵ Pa
work done on the gas
=external pressure x change in volume
= 10⁵ x 4.33 X 10⁻³
=4.33 x 10²
433 J
Using the formula
Q = ΔE + W , Q is heat added , ΔE is change in internal energy , W is work done by the gas
Given
Q = - 124 J ( heat is released so negative )
W = - 433 J . ( work done by gas is negative, because it is done on gas )
- 124 = ΔE - 433
ΔE = 433 - 124
= 309 J
There is increase of 309 J in the internal energy of the gas.
Answer:
the velocity (magnitude and direction) of the ball) just before the collision is 
The velocity (magnitude and direction) of the ball) just after the collision is 
Explanation:
According to the law of conservation of energy;
Thus; the velocity (magnitude and direction) of the ball) just before the collision is
Since, Air resistance is negligible, and the collision is elastic.
The equation for the conservation of momentum and energy can be expressed as:
![v_f = [\frac{m_1 -m_2}{m_1+m_2}]v_i\\\\v_f = [\frac{m_{ball} -m_{block}}{m_{ball}+m_{block}}]v_i\\\\v_f = [\frac{1.6 -2.5}{1.6+2.5}]*5.144\\\\](https://tex.z-dn.net/?f=v_f%20%3D%20%5B%5Cfrac%7Bm_1%20-m_2%7D%7Bm_1%2Bm_2%7D%5Dv_i%5C%5C%5C%5Cv_f%20%3D%20%20%5B%5Cfrac%7Bm_%7Bball%7D%20-m_%7Bblock%7D%7D%7Bm_%7Bball%7D%2Bm_%7Bblock%7D%7D%5Dv_i%5C%5C%5C%5Cv_f%20%3D%20%5B%5Cfrac%7B1.6%20-2.5%7D%7B1.6%2B2.5%7D%5D%2A5.144%5C%5C%5C%5C)
The velocity (magnitude and direction) of the ball) just after the collision is
