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Contact [7]
2 years ago
5

Earth is in a habitable zone that allows our planet to have liquid water. What is this zone called?

Chemistry
2 answers:
andrew-mc [135]2 years ago
8 0

Answer:

The Goldilocks Zone

Explanation:

I know how it sounds, please believe me!!!

Virty [35]2 years ago
5 0
The answer is in the question, it is the “habitable zone”
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HELP PLEASE THIS IS CONFUSING
Rasek [7]

Number of moles = 8.3 x 10⁻¹³

<h3>Further explanation </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³  particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's =  6.02.10²³

5 x 10¹¹ atoms of Silver :

\tt mol=\dfrac{5\times 10^{11}}{6.02\times 10^{23}}=8.3\times 10^{-13}

5 0
3 years ago
1 A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circul
LenKa [72]
The correct answer to this question is that the length of 14 is it’s half Which would be 7
6 0
2 years ago
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

Mass of methane CH4 (g) = 80.0 g.

Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

6 0
1 year ago
The average kinetic energy of gas particles depends on which factor?
saveliy_v [14]
Only the temperature of gas
4 0
3 years ago
Balance the following chemical equation by providing the correct coefficients.
Charra [1.4K]

Answer:

[2 ]Na+[2 ]H2O -> [ 2] NaOH + [1]H2

5 0
3 years ago
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