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2 years ago

Which of these diagrams best represents the steps in the formation of planets?

2 answers:

6 0

The right answer for the question that is being asked and shown above is that: "C) The clouds of dust and gases rotate at high speed > The clouds condense > The sun is born > The planets are born " This is the diagram that best represents the steps in the formation of planets

Leviafan [203]2 years ago

4 0

Answer:

D) The clouds of gases condense > The clouds rotate at high speed > The clouds flatten into an elliptical disc > The planets are born

Explanation:

Planets are formed from Planetary nebula. The cloud of dust and gases condenses under its own weight. The condensed matter starts rotating at high speeds and gathers more mass. The core forms the star and rest of it eventually flattens into an elliptical disc from which planet is born. Thus, the correct sequence is: D) The clouds of gases condense > The clouds rotate at high speed > The clouds flatten into an elliptical disc > The planets are born.

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Can someone spell the word hi for me I’ll give you 30 points

jasenka [17]

Answer:

hi poop

Explanation:

3 0

3 years ago

Read 2 more answers

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

ra1l [238]

Answer:

a) t = 4.16 s

b) x = 141.51 m

Explanation:

Given

v = 21.5 m/s

x0 = 52.0 m

a = 6.0 m/s²

a) Motorcycle

x = v0*t + (a*t²/2)

x = 21.5t + (6*t²/2)

x = 21.5t + 3t² (I)

Car

x = x0 + v0*t

x = 52 + 21.5t (II)

then we can apply I = II

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

⇒ t = 4.16 s

b) We can use I or II, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

8 0

3 years ago

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction

zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, $F_c=\frac{mv^2}{R}$

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

$f=\mu N$

As there is no vertical motion, therefore, $N=mg$ . So,

$f=\mu mg$

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816$

Therefore, option (c) is correct.

7 0

3 years ago

Nicolaus Copernicus was a Polish astronomer who is best known for the theory that the sun is near the center of the universe and

serg [7]

Answer:

DOUBLE CHECK BECUASE IM ONLY 68.030303039999999% SURE!!!

(ANSWER IS HERE) ( D) It lacked practical examples in supporting theory

Know it's not B becuase there was no scientific community back then.

Know it's not C becuase it actully had lots of evidence.

But I'm not sure about A

3 0

3 years ago

Two objects have a force of gravity of 100 N. If the distance between both objects decreases by a factor of 7, while the masses

Shkiper50 [21]

The gravitational force F between two masses M and m a distance r apart is

F = G M m / r ²

Decrease the distance by a factor of 7 by replacing r with r / 7, and decrease both masses by a factor of 8 by replacing M and m with M / 8 and m / 8, respectively. Then the new force F* is

F* = G (M / 8) (m / 8) / (r / 7)²

F* = (1/64 × G M m) / (1/49 × r ²)

F* = 49/64 × G M m / r ²

In other words, the new force is scaled down by a factor of 49/64 ≈ 0.7656, so the new force has magnitude approx. 76.56 N.

8 0

2 years ago