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I am Lyosha [343]
3 years ago
8

Which of these diagrams best represents the steps in the formation of planets?

Physics
2 answers:
sineoko [7]3 years ago
6 0
The right answer for the question that is being asked and shown above is that: "<span>C) The clouds of dust and gases rotate at high speed > The clouds condense > The sun is born > The planets are born " This is the </span><span>diagram that best represents the steps in the formation of planets</span>
Leviafan [203]3 years ago
4 0

Answer:

D) The clouds of gases condense > The clouds rotate at high speed > The clouds flatten into an elliptical disc > The planets are born

Explanation:

Planets are formed from Planetary nebula. The cloud of dust and gases condenses under its own weight. The condensed matter starts rotating at high speeds and gathers more mass. The core forms the star and rest of it eventually flattens into an elliptical disc from which planet is born. Thus, the correct sequence is: D) The clouds of gases condense > The clouds rotate at high speed > The clouds flatten into an elliptical disc > The planets are born.

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With the switch closed, how does the voltage across the 20-ω resistor compare to the voltage across the 10-ω resistor?
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In a series connection, the voltage is greater across a high-resistance resistor. Therefore, the voltage is much greater for the 20-ohm resistor. However,if it is a parallel circuit, the voltage is just the same for both resistors.
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3 years ago
When touched by a plastic straw, the metal sphere will do what?
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3 years ago
Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carryin
Vedmedyk [2.9K]

Answer:

The correct answer is 2.8*10^{-5}ms^{-1}

Explanation:

The formula for the electron drift speed is given as follows,

u=I/nAq

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is 8.93/63.5 molcm^{-3}. Converting this number to m³ using very elementary unit conversion we get 140384molm^{-3}. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}

if we convert the area from mm³ to m³ we get A=80*10^{-6}m^{2}.So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,

u=30/(8.45*10^{28}*80*10^{-6}*1.602*10^{-19})\\u=2.8*10^{-5}m.s^{-1}

which is our final answer.

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3 years ago
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Tema [17]

Answer:

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