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mario62 [17]
2 years ago
10

Help Please... giving brainliest..

Chemistry
2 answers:
julia-pushkina [17]2 years ago
5 0

Answer:

1. Pecan 1 and Pecan 4

2. Farmer can take pecan 1 and pecan 4 DNA then combine it to grow a new pecan that produce higher of nut cluster and have rich and buttery Flavored nut.

3. Selective Breeding

WINSTONCH [101]2 years ago
3 0

1) Well, you need to logically think about which of the pecan trees would be better. Tree 3 may have more clusters but they taste bitter so this is out of the option. So Tree 4 and Tree 1 would be best because they both have rich and buttery tastes and they both have a lot of clusters.

2) Not quite sure about this one, sorry :(

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Starting with 0.250L of a buffer solution containing 0.250 M benzoic acid (C 6H 5COOH) and 0.20 M sodium benzoate (C 6H 5COONa),
Zigmanuir [339]

Answer:

pH = 4.05

Explanation:

The pH of the benzoic buffer can be determined using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is -logKa = 4.187</em>

pH = 4.187 + log [Sodium Benzoate] / [Benzoic Acid]

<em>Where [] can be understood as moles of each specie.</em>

Thus, to find pH of the buffer we need to calculate moles of benzoic acid and sodium benzoate.

<em>Initial moles:</em>

<em />

Initial moles of benzoic acid and sodium benzoate are:

Acid: 250mL = 0.250L ₓ (0.250 moles / L) = <em>0.0625 moles of benzoic acid</em>

Benzoate : 250mL = 0.20L ₓ (0.250 moles / L) = <em>0.050 moles of sodium benzoate</em>

<em>Moles after reaction:</em>

Now, 0.0250L×(0.100mol/L) = 0.0025 moles of HCl are added to the buffer reacting with sodium benzoate, C₆H₅COONa, producing more benzoic acid, as follows:

HCl + C₆H₅COONa → C₆H₅COOH + NaCl

That means after reaction moles of both species are:

Benzoic acid: 0.0625 mol + 0.0025mol (Moles produced) = 0.065 moles

Sodium Benzoate: 0.050mol - 0.0025mol (Moles that react) = 0.0475 moles

Replacing in H-H equation:

pH = 4.187 + log [0.0475] / [0.065]

pH = 4.05

5 0
3 years ago
The cells of smokers often use anaerobic respiration more than the cells of non-smokers. Suggest one chemical in cigarette smoke
valentina_108 [34]

Answer:

Nicotine

Explanation:

8 0
3 years ago
Consider the reaction below in a closed flask. At 200 o C, the equilibrium constant (Kp) is 2.40 × 103 . 2 NO (g)  N2 (g) + O2
olga55 [171]

Explanation:

Since, the given reaction is as follows.

       2NO(g) \rightleftharpoons N_{2}(g) + O_{2}(g)

Initial:    36.1 atm                 0          0

Change:    2x                      x           x

Equilibrium: (36.1 - 2x)       x            x

Now, expression for K_{p} of this reaction is as follows.

            K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}

As the initial pressure of NO is 36.1 atm. Hence, partial pressure of O_{2} at equilibrium will be calculated as follows.

              K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}

        2.40 \times 10^{3} = \frac{x \times x}{(36.1 - 2x)^{2}}

                 x = 18.1 atm

Thus, we can conclude that partial pressure of O_{2} at equilibrium is 18.1 atm.

5 0
3 years ago
Read 2 more answers
Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a cataly
Lyrx [107]

<u>Answer: </u>0.0285 moles of HCl is present in given amount of solution.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles

Hence, 0.0285 moles of HCl is present in given amount of solution.

4 0
3 years ago
True or False: <br><br> Rain is the only form of precipitation that this pollutant takes.​
Nady [450]

Answer:

I’m not sure probably false

Explanation:

4 0
3 years ago
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