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svetlana [45]
3 years ago
8

Carbon monoxide is 1. an atom, an element and a mixture. 2. a molecule, element and a pure substance. 3. an atom, a compound and

a mixture. 4. an atom, an element and a pure substance. 5. a molecule, a compound and a mixture. 6. a molecule, a compound and a pure substance.
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

The correct answer is option (6).

Explanation:

A molecule is group of atoms of same or different kinds of element.

In carbon monoxide there is a single carbon atom and single oxygen atom. Hence, a molecule.

Compound is defined as a chemical specie which is made by the combination of different atoms.

As we can see from the chemical formula of carbon monoxide is made up of two atom of different elements that is carbon and oxygen.

A pure substance is defined as the substance which is formed by same or different type of atoms which are chemically combined in a fixed ratio by mass. They have definite set of properties.

C+\frac{1}{2}O_2\rightarrow CO

1 mole of carbon combined with 0.5 moles of oxygen gas to give carbon monoxide gas.

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3 0
3 years ago
How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
3 years ago
What role does the activation energy play in chemical reactions?
Tatiana [17]
The activation energy is the minimum amount of energy that particles must have in order for them to participate in a chemical reaction. During chemical reactions bonds are broken and formed. Particles must collide with sufficient energy in order for the initial bonds to be broken. The activation energy is that that initial minimum energy that the particles can have in order for the bonds to be broken. Stronger bonds would require more energy to be broken and therefore the activation energy for such would be higher.
7 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
2 years ago
Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has pre
antiseptic1488 [7]
However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.850 ...
7 0
3 years ago
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