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svetlana [45]
3 years ago
8

Carbon monoxide is 1. an atom, an element and a mixture. 2. a molecule, element and a pure substance. 3. an atom, a compound and

a mixture. 4. an atom, an element and a pure substance. 5. a molecule, a compound and a mixture. 6. a molecule, a compound and a pure substance.
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

The correct answer is option (6).

Explanation:

A molecule is group of atoms of same or different kinds of element.

In carbon monoxide there is a single carbon atom and single oxygen atom. Hence, a molecule.

Compound is defined as a chemical specie which is made by the combination of different atoms.

As we can see from the chemical formula of carbon monoxide is made up of two atom of different elements that is carbon and oxygen.

A pure substance is defined as the substance which is formed by same or different type of atoms which are chemically combined in a fixed ratio by mass. They have definite set of properties.

C+\frac{1}{2}O_2\rightarrow CO

1 mole of carbon combined with 0.5 moles of oxygen gas to give carbon monoxide gas.

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If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
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Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

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m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

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