Answer: h = 3.34 m
Explanation:
If the hat is thrown straight up, then at its highest point it has no motion and no kinetic energy. All energy is potential energy
PE = mgh
h = PE/mg = 4.92 / (0.150(9.81)) = 3.34352... ≈3.34 m
Answer:
(a). Z = 54.54 ohm
(b). R = 36 ohm
(c). The circuit will be Capacitive.
Explanation:
Given data
I = 2.75 A
Voltage = 150 V
rad = 48.72°
(a). Impedance of the circuit is given by
![Z = \frac{V}{I}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BV%7D%7BI%7D)
![Z = \frac{150}{2.75}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B150%7D%7B2.75%7D)
Z = 54.54 ohm
(b). We know that resistance of the circuit is given by
![R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7BZ%7D%7B%5Csqrt%7B1%20%2B%20%5Ctan%5E%7B2%7D%5Cphi%20%7D%20%7D)
Put the values of Z &
in above formula we get
![R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B54.54%7D%7B%5Csqrt%7B1%20%2B%20%5Ctan%5E%7B2%7D%20%28%20%5C%2048.72%29%20%7D%20%7D)
R = 36 ohm
(c). Since the phase angle is negative so the circuit will be Capacitive.
Answer:570.54 N
Explanation:
Given
mass of man=76 kg
![\theta =50^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D50%5E%7B%5Ccirc%7D)
As man is standing over inclined building therefore
its weight has two components i.e. sin and cos component
Force perpendicular to inclined wall
![F=mgcos\theta =76\times 9.8\times \sin 50](https://tex.z-dn.net/?f=F%3Dmgcos%5Ctheta%20%3D76%5Ctimes%209.8%5Ctimes%20%5Csin%2050)
F=570.54 N
Because the number of valence electrons of an element determines the properties and in particular the reactivity of that element.
In fact, elements of the first group (i.e. only one valence electron) have high reactivity, because they can easily give away their valence electron to atoms of other elements forming bonds. On the contrary, elements of the 8th group (noble gases) have their outermost shell completely filled with electrons, so they do not have valence electrons, and they have little or no reactivity at all.
The force applied to the second ball by the first ball is 6.734 × 10^-4 N.
<h3>What is impulse of force?</h3>
The impulse of force is defined as the sum of the average force and the duration it is applied.
If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.
Given that: mass of a metal sphere: m = 0.026 kg.
Initial speed of the sphere: u = 3.7 m/s.
When the sphere stops completely, its change in momentum = mu - 0
= 0.026×3.7 N-s.
= 0.0962 N-s.
As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied to the second ball =
change in momentum of 1st ball × time of contact
= 0.0962 × 0.007 N
= 0.0006734 N
= 6.734 × 10^-4 N.
Hence, the force applied to the second ball is 6.734 × 10^-4 N.
Learn more about impulse force here:
brainly.com/question/29787329
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