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alekssr [168]
3 years ago
10

Zeros between a decimal point and a non-zero number are (blank) significant

Physics
1 answer:
ipn [44]3 years ago
3 0
<span>Zeros between a decimal point and a non-zero number are *radical numbers*
:) Hope this helps :)</span>
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A negatively charged particle is moving to the right, directly above a wire have a current flowing to the right. In which direct
Varvara68 [4.7K]

Answer:

C) upward

Explanation:

The problem can be solved by using the right-hand rule.

First of all, we notice at the location of the negatively charged particle (above the wire), the magnetic field produced by the wire points out of the page (because the current is to the right, so by using the right hand, putting the thumb to the right (as the current) and wrapping the other fingers around it, we see that the direction of the field above the wire is out of the page).

Now we can apply the right hand rule to the charged particle:

- index finger: velocity of the particle, to the right

- middle finger: direction of the magnetic field, out of the page

- thumb: direction of the force, downward --> however, the charge is negative, so we must reverse the direction --> upward

Therefore, the direction of  the magnetic force is upward.

3 0
3 years ago
Never mind i dont need help anymore
Usimov [2.4K]
Yay good for you!!!!
8 0
3 years ago
A student puts a beaker of boiling water where it touches a block of ice. Which two statements are true? A. Thermal energy will
rodikova [14]

Answer: C and D

Explanation: I’m pretty sure it’s C and D I got the same question but cold water let me know please, thanks!

6 0
4 years ago
Read 2 more answers
The history of Sir Isaac Newton’s study of gravity does which of the following?
ipn [44]

A. Illustrates how a theory becomes a law

5 0
3 years ago
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Un cable está tendido sobre dos postes colocados con una separación de 10 m. A la mitad del cable se cuelga un letrero que provo
lisabon 2012 [21]

Answer:

El peso del cartel es 397,97 N

Explanation:

La tensión dada en cada segmento del cable = 2000 N

El desplazamiento vertical del cable = 50 cm = 0,5 m

La distancia entre los polos = 10 m

La posición del letrero en el cable = En el medio = 5

El ángulo de inclinación del cable a la vertical = tan⁻¹ (0.5 / 5) = 5.71 °

El peso del letrero = La suma del componente vertical de la tensión en cada lado del letrero

El peso del signo = 2000 × sin (5.71 grados) + 2000 × sin (5.71 grados) = 397.97 N

El peso del signo = 397,97 N.

8 0
3 years ago
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