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3 years ago

What are some physical and chemical changes that occur as a car ages?

Chemistry

2 answers:

slamgirl [31]3 years ago

6 0

Answer:physical: a part falling off or changing a tire. chemical:rust

Explanation:

alekssr [168]3 years ago

6 0

Answer:

Physical changes that occur as car ages are the paint of the car started to get fade and car tires start losing its grip.

Chemical changes that occur as a car ages is the element O (Oxygen) and Al (Aluminum) react with one another to form Al2 O3 (rust).

When the car ages Most Common physical and chemical Car Problems and car complaints are discussed below:

Excessive Oil Consumption.
Radiator Leaks.
Cracked Windshield.
Malfunctioning Sensors.
Paint Problems.
Dead Battery.

These are some most common car ages issues which are discussed above.

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Are two atoms of the same element identical??

Neko [114]

No. Although two such atoms are essentially chemically identical (they will chemically react in the same way), they are not completely identical.

3 0

2 years ago

234+34.1 add and round to 2 significant figures

marin [14]

Like this? 234+34.1= 268.1 then round. If it is less than 5 then you round down if it is more then you round up. Because it is less the final number would be 268.1=268

3 0

3 years ago

A rectangular block has the following dimensions: 3.21 dm, 5.83 cm, and 1.84 in. The block has a mass of 1.94 kg. What is the de

spin [16.1K]

The density of the rectangular block in g/mL is 7.0.

Given the following data:

Mass of block = 22.8 gra1.94 kg

Length of block = 3.21 cm

Width of block = 5.83 cm

Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

$Volume = length$ × $width$ × $height$

Conversion:

1 in = 2.54 cm

5.83 in = X cm

Cross-multiplying, we have:

$X = 2.54(5.83)\\\\X = 14.81 \; cm$

$Volume = 3.21$ × $5.83$ × $14.81$

Volume = 277.16 cubic centimeters.

Note: Milliliter (mL) is the same as cubic centimeters.

1000 grams = 1 kg

Y grams = 1.94 kg

Cross-multiplying, we have:

Y = 1940 grams

Now, we can find the density:

$Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}$

Density = 7.0 g/mL

Therefore, the density of the rectangular block in g/mL is 7.0.

4 0

2 years ago

To produce 3.00 L of a 1.90 M solution of sodium hydroxide (NaOH), how many grams of sodium hydroxide must be dissolved?

ElenaW [278]

Answer is 81234 so hole this helps

7 0

3 years ago

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re

Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2 = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = $\frac{Presssure due to CO_2}{Total pressure}$

CO2 = $\frac{0.536}{0.729}$

= 0.735

Also; for Kr ; we have

Kr = $\frac{0.193}{0.729}$

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 * 83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is as follows:

% CO2 = $\frac{32.34}{54.54}$ * 100 %

= 0.5930

= 59.30%

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr = $\frac{22.20}{ 54.54}$ * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0

3 years ago