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Leokris [45]
4 years ago
5

How do you work out velocity using kinetic energy?

Physics
1 answer:
marishachu [46]4 years ago
6 0
You just use a bit of algebra. Kinetic energy is KE = (1/2) (mass) (speed squared). Multiply each side by (2/mass) and you have 2KE/mass=speed-squared. The square root of both sides then gives you the speed in terms of the kinetic energy.
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When spray is applied to a car, the paint has a negative charge and the surface of the car has a positive charge. Some processes
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Answer:

Based on the properties electrically charged particles, we have that unlike charges attract and like charges repel each other. In order for proper application of an electrostatically negatively charged paint to be properly applied on the metal body surface of a vehicle, require that for attraction, the surface of the vehicle should be grounded and positively charged so as to effectively attract the negatively charged paint particles as it exits the nozzle, to form a strong attachment with the positively charged surface of the vehicle

Explanation:

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3 years ago
The gravitational force between two objects is 13.6x10-8N when they are 8cm apart. What would be the force between them when the
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Answer:

F {(0.24)}^{2}  = 13.6 \times  {10}^{ - 8} \\  F  =  \frac{13.6 \times  {10}^{ - 8}}{ {(0.24)}^{2} }N

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The image shows how Earth orbits the Sun. Points W and X are the same distance from the Sun.
Ksju [112]

<u>Answer:</u>


This figure shows the Second Kepler’s Law of Planetary Motion, <em>The line that joins the planet with the Sun sweeps equal areas in equal times</em>.  

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4 years ago
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To find amplitude, measure
polet [3.4K]
<span>from a trough to the rest position and from a crest to the rest position.

</span>
3 0
4 years ago
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A horizontal spring with a 10000 N/m spring constant is compressed 0.08 m, and a 12-kg block is placed against it. When the bloc
agasfer [191]

Answer:

4.04m

Explanation:

First you calculate the velocity of the block when it leaves the spring. You calculate this velocity by taking into account that the potential energy of the spring equals the kinetic energy of the block, that is:

U=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(10000N/m)(0.08m)^2}{12kg}}=2.3\frac{m}{s}

To find the distance in which the block stops you use the following expression (net work done by the friction force is equal to the difference in the kinetic energy of the block):

W_{T}=\Delta K\\\\F_f d=\frac{1}{2}m[v^2-v_o^2]\\\\d=\frac{mv^2}{2F_f}

where Ff is the friction force. By replacing the values of the parameters you obtain:

d=\frac{(12kg)(2.3m/s)^2}{2(8N)}=3.96m

hence, the distance to the original position is 3.96m+0.08m=4.04m

3 0
3 years ago
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