Answer:
The voltage ( or potential difference) V increases while the charge Q decreases.
Explanation:
The capacitance C of a capacitor is defined as the measure to which the capacitor can store charges. For a parallel-plate capacitor it is given by the following relationship;
where A is the surface area of the plates, d is their distance of separation, is the permittivity of free space and
is relative permittivity.
Also, the capacitance of a capacitor can be expressed in the form of equation (2)
where Q is the charge stored and V is the potential difference.
By combining (1) and (2) and making d the subject of formula, we obtain the following;
By observing (3), it is seen that the distance d of separation between the plates is directly proportional to the potential difference V and inversely proportional to the charge stored Q. This implies that an increase in the distance d of separation will bring about an increase the the voltage or potential difference V and a decrease in the charge Q.