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Karolina [17]
3 years ago
12

Please help on this one?

Physics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

D. An image that is smaller than the object and is behind the mirror

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A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?
krek1111 [17]
<h2>Answer:</h2>

4.2 C

<h2>Explanation:</h2>

The charge (Q) moving is the product of the current(I) flowing through the torso of the person and the time taken (t) for the flow.

i.e

Q = I x t

Where;

I = current = 14.0A

t = time taken  = 0.0300s

Substituting the values of I and t into the equation above gives

Q = 14.0 x 0.0300

Q = 4.2 C

Therefore quantity of charge moving is 4.2 C

4 0
3 years ago
what happens to the specific heat capacity of a material if it changes state? i.e. from solid to liquid
Zigmanuir [339]

Answer:

A solid substance at its melting point has less energy than the same mass of the substance when it is a liquid at the same temperature. ... This heat energy allows the change of state to happen, and the temperature remains constant during the process.

Explanation:

6 0
3 years ago
Why would a person choosing to take a line of credit want to choose one that charges simple interest
krok68 [10]

Answer:

Lines of credit are unsecured loans. That means the bank is taking a huge risk. The bank has to be certain the borrower has a credit history that indicates (s)he will pay back the loan

8 0
2 years ago
Which statement correctly describes the relationship between thermal energy and particle movement?
zhuklara [117]

As thermal energy increases, there is more particle movement. As thermal energy increases, there is more particle movement. As thermal energy increases, there is less particle movement.

Sure hope this helps you

5 0
2 years ago
An ore sample weighs 17.50 N in air. When the sample
zysi [14]

Answer with Explanation:

We are given that

Weight of an ore sample=17.5 N

Tension in the cord=11.2 N

We have to find the total volume and the density of the sample.

We know that

Tension, T=W-F_b

F_b=buoyancy force

T=Tension force

W=Weight

By using the formula

11.2=17.5-F_b

F_b=17.5-11.2=6.3 N

F_b=V_{object}\times \rho_{water}\cdot g

Where

V_{object}=Volume of object

\rho_{water}=1000 kgm^{-3}=Density of water

g=9.8 ms^{-2}=Acceleration due to gravity

Substitute the values then we get

6.3=9.8\times 1000\times V_{object}

V_{object}=\frac{6.3}{9.8\times 1000}=6.43\times 10^{-4} m^3

Volume of sample=6.43\times 10^{-4} m^3

Density of sample,\rho_{object}=\frac{Mass}{volume_{object}}

Where mass of ore sample=1.79 kg

Substitute the values then, we get

\rho_{object}=\frac{1.79}{6.43\times 10^{-4}}=2.78\times 10^3 kg/m^3

Density of the sample=2.78\times 10^{3} kgm^{-3}

7 0
3 years ago
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