How does a sun form make it a short paragraph
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<h3>Answer:</h3>
There is One electrophilic center in acetyl chloride.
<h3>Explanation:</h3>Electrophile is defined as any specie which is electron deficient and is in need of electrons to complete its electron density or octet. The main two types of electrophiles are those species which either contain positive charge (i.e. NO₂⁺, Cl⁺, Br⁺ e.t.c) or partial positive charge like that contained by the sp² hybridized carbon of acetyl chloride shown below in attached picture.
In acetyl chloride the partial positive charge on sp² hybridized carbon is generated due to its direct bonding to highly electronegative elements *with partial negative charge) like oxygen and chlorine, which tend to pull the electron density from carbon atom making it electron deficient and a good electrophile for incoming nucleophile as a center of attack.
The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂
This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate
Now, we will calculate the number of moles of barium hydroxide present.
Mass of barium hydroxide (Ba(OH)₂) = 20 g
Using the formula
Molar mass of Ba(OH)₂ = 171.34 g/mol
∴ Number of moles of Ba(OH)₂ present =
Number of moles of Ba(OH)₂ present = 0.116727 mole
Now,
Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate
Then,
0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate
2 × 0.116727 = 0.233454 mole
∴ Number of moles of NH₄NO₃ required is 0.233454 mole
Now, for the mass of ammonium nitrate (NH₄NO₃) required
From the formula
Mass = Number of moles × Molar mass
Molar mass of NH₄NO₃ = 80.043 g/mol
∴ Mass of NH₄NO₃ required = 0.233454 × 80.043
Mass of NH₄NO₃ required = 18.68636 g
Mass of NH₄NO₃ required ≅ 18.7g
Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g
Learn more on determining mass of reactant required here: brainly.com/question/11232389