Answer:
v = 7.85 × 10¹⁴ Hz
Explanation:
The first three energy level can be represented as follows:
⇅ ------> n₄ = 4
⇅ ------> n₃ = 3
⇅ ------> n₂ = 0
ΔE = hv =
ΔE = hv =
ΔE = hv =
ΔE = hv =
where h = planck constant = J.s
mass (m) =
e = 0.904 nm =
hv =
hv =
hv =
hv = J
v =
v =
v =
v = 7.85 × 10¹⁴ Hz (since s⁻¹ is equivalent to 1 Hz)
Thus, the frequency of an electronic transition from the highest-occupied orbital to the lowest-unoccupied orbital = 7.85 × 10¹⁴ Hz
Answer:
No
Explanation:
No, this is an addition reaction
HC≡CH + 2H-H ----> H3C - CH3
Answer:
WHERE IS THE EQUATION ?????
Explanation:
The correct answer is true, you need to be able to stop it, an object in motion remains in motion unless acted upon