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klasskru [66]
3 years ago
7

A boat loaded with a barrel of water floats in a swimming pool. When the water in the barrel is poured overboard, the swimming p

ool level will _____.
Question 6 options:

fall

remain unchanged

rise
Physics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer: Remain unchanged

Explanation:

The boat with water barrel overboard floats in swimming pool when weight of the water displaced by the boat is equal to the buoyant force acting on the boat.

When the water in the barrel is poured overboard, the level of the swimming pool level would remain unchanged as the weight of the boat  with the water and barrel would remain unchanged ( as the density and volume of the whole system remains same) and hence, the weight of the water (of the swimming pool) displaced by the boat would remain same.

A boat loaded with a barrel of water floats in a swimming pool. When the water in the barrel is poured overboard, the swimming pool level will <u>remain unchanged. </u>

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A turntable has an angular velocity of 3.5 rad/s. A dust bunny is on the disk of the turntable at a distance of 0.2m from the ce
diamong [38]

Answer:

E. 0.25

Explanation:

Given that

Angular speed ω = 3.5 rad/s

Distance ,r= 0.2 m

Lets take mass of dust bunny = m

We know that

Radial force F = m ω² r

The friction force on the dust bunny Fr

Fr= μ m g

To getting slung off  dust bunny from disk

m ω² r =  μ m g

ω² r =  μ  g

3.5²  x 0.2 =  μ x 10                        ( take g =10 m/s²)

μ = 0.245

μ = 0.25

Therefore answer is E

E. 0.25

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3 years ago
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shutvik [7]
Correct you can't share people's information without their permission.
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3 years ago
A 20kg metal block is placed on a horizontal surface. The block just begins to slide when horizontal force of 100N is applied to
guajiro [1.7K]

Answer:

See the photo

Explanation:

I can't do the exercise a because you need the Fs to calculate the coefficient of static friction.

4 0
3 years ago
Sometimes my music is played value can feel your body shaking explain what is happening in terms of resonance?
Jet001 [13]

Answer:

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Explanation:

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8 0
3 years ago
A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep
salantis [7]
The box is kept in motion at constant velocity by a force of F=99 N. Constant velocity means there is no acceleration, so the resultant of the forces acting on the box is zero. Apart from the force F pushing the box, there is only another force acting on it in the horizontal direction: the frictional force F_f which acts in the opposite direction of the motion, so in the opposite direction of F.
Therefore, since the resultant of the two forces must be zero,
F-F_f=0
so
F=F_f

The frictional force can be rewritten as
F_f = \mu m g
where m=50 kg, g=9.81 m/s^2. Re-arranging, we can solve this equation to find \mu, the coefficient of dynamic friction:
\mu =  \frac{F}{mg}= \frac{99 N}{(50 kg)(9.81 m/s^2)}  =0.20
4 0
3 years ago
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