Answer:
6.50 grams of the compound X is nitrogen
Explanation:
Step 1: Data given
Mass of compound X = 37.8 grams
Compound contains 17.2 % N
Step 2: Calculate mass of nitrogen
Mass nitrogen = % Nitrogen * total mass
Mass nitrogen = 17.2 % * 37.8 grams = 0.172 * 37.8 grams
Mass nitrogen = 6.50 grams
6.50 grams of the compound X is nitrogen
Answer:
The value of n in the hydrate formula is 5 ,
.
Explanation:

Mass of hydrate of copper sulfate = 14.220 g
Moles of hydrate of copper sulfate =
Mass of copper sulfate after heating = 8.9935 g
Moles of copper sulfate = 

Solving for n, we get:
n = 5
The value of n in the hydrate formula is 5 ,
.
Answer:
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
Explanation:
<em>Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of MgSO₃ and HI are mixed.</em>
When MgSO₃ reacts with HI they experience a double displacement reaction, in which the cations and anions of each compound are exchanged, forming H₂SO₃ and MgI₂. At the same time, H₂SO₃ tends to decompose to H₂O and SO₂. The complete molecular equation is:
MgSO₃(aq) + 2 HI(aq) ⇄ MgI₂(aq) + H₂O(l) + SO₂(g)
In the complete ionic equation, species with ionic bonds dissociate into ions.
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)