How would these cells appear under a microscope at a higher magnification.
1 answer:
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Answer:
The dissociation constant for the acid ( experimental ) is 1.45 lit/mol
Explanation:
The value of dissociation constant can be calculated as,
= C × ∝²
Where, C = concentration of the solution = 0.329M
∝ = Degree of dissociation
again , Degree of dissociation can be obtained form :
= C × ∝
∝ =
∝ = = 7.072
So, now = C × ∝²
= 0.329 ×( 7.072)²
= 1.45 lit/ mol