Total weight of the mixture of sand and salt = 5.25 g
Weight of sand separated = 3.64 g
Weight of the salt in the mixture = (5.25 - 3.64) g
= 1.61 g
Then the percentage of sand in the sample = [(3.64/5.25) * 100] percent
= 69.33%
So the percentage of sand in the total mixture of sand and salt is 69.33%.
Answer:
. CuO
Explanation:
Since oxygen also has -2 the valency will cancel out the +2 on Cu leaving CuO
I would say #3 I’m sorry if it’s wrong tho
CS2 + 3O2 = CO2 + 2SO2
1 mole of CS2 gives 1 mole of CO2
12 + 2(32) = 76g of CS2 yields 44 g of CO2
Theoretically 1 g of CS2 yields 44/76 g CO2
Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g
So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).
The 30g cannot be right . This is experimental err.
Do it urself ;) jdhdhdhdhdhhdhdhdhdhdhdhdhdhgdhd
