Answer:
- Absolute zero is - 459.67 °F
Explanation:
<u>1) Convert absolute zero to celsius:</u>
- 0 K = - 273.15°C ( this is per definition of the scale)
<u>2) Convert - 273.15°C to Fahrenheit:</u>
- T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=
- T (°F) = - 273.15 × 1.8 + 32 = - 459.67 °F ← answer
A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (
).
Utilize the titration method of
in view that we're given the concentrations of every compound and the quantity of
. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.
- M1 = initial mass
- V1= initial volume
- M2 = final mass
- V2= final volume

- (0.138)(V1) = (0.205)x(26.0)
- V2=(0.205)x(26.0)\ 0.138
- V2 = 47.10 M/L
- The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L
Read more about the neutralization:
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Answer:
4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.
Explanation:
Half life (t1/2) = 8 days
Original mass (No) = 64 g
Elapsed time (t) = 32 days
Mass remaining (Nt) = ?
Using the half life equation we can obtain the mass remaining (Nt)
Nt = No (1/2) ^t/t1/2
Substituting the values, we have;
Nt = 64 * ( 1/2 ) ^32/8
Nt = 64 * (1/2) ^4
Nt = 64 * 0.0625
Nt = 4 g
So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.
6 grams of Carbon is it’s mass
<u>Explanation:</u>
First we have to divide the given number of atoms
by the Avogadro's number
, so that we will get the number of moles as 1/2.
Then the 1/2 moles of carbon is multiplied by the molar mass of Carbon which is 12 g/mol, we will get the mass of carbon as 6 grams.
So the mass of the carbon obtained is 6 grams.