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xenn [34]
2 years ago
8

Can you give me more explanation in the picture?

Chemistry
1 answer:
PolarNik [594]2 years ago
5 0
Read the paper more carefully if you don't understand it
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Absolute zero is what temperature on the fahrenheit scale?
vampirchik [111]

Answer:

  • Absolute zero is - 459.67 °F

Explanation:

<u>1) Convert absolute zero to celsius:</u>

  • 0 K = - 273.15°C ( this is per definition of the scale)

<u>2) Convert - 273.15°C to Fahrenheit:</u>

  • T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=

  • T (°F) = - 273.15 × 1.8 + 32 = - 459.67 °F ← answer

8 0
2 years ago
what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?
Law Incorporation [45]

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (M1V1 = M2V2).

Utilize the titration method of M1V1 = M2V2 in view that we're given the concentrations of every compound and the quantity of KOH. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

  • M1 = initial mass
  • V1= initial volume
  • M2 = final mass
  • V2= final volume
  • (M1V1 = M2V2)
  • (0.138)(V1) = (0.205)x(26.0)
  • V2=(0.205)x(26.0)\ 0.138
  • V2 = 47.10 M/L
  • The final value of Volume needed for neutralization of nitric acid solution is  V2 = 47.10 M/L

Read more about the neutralization:

brainly.com/question/23008798

#SPJ4

4 0
1 year ago
Why do you have to have a certain number of reactants on one side?
Debora [2.8K]

Answer:

EWQEQW

Explanation:

WEQWE

3 0
2 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

Half life (t1/2) = 8 days

Original mass (No) = 64 g

Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

Nt = 64 * (1/2) ^4

Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
If you have 3.011x1023 atoms of carbon what would you expect it’s mass to be
devlian [24]

6 grams of Carbon is it’s mass

<u>Explanation:</u>

First we have to divide the given number of atoms (3.011 \times 10^2^3) by the Avogadro's number (6.022 \times 10^2^3), so that we will get the number of moles as 1/2.

Then the 1/2 moles of carbon is multiplied by the molar mass of Carbon which is 12 g/mol, we will get the mass of carbon as 6 grams.

So the mass of the carbon obtained is 6 grams.

4 0
3 years ago
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