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Butoxors [25]
3 years ago
5

Do all alloys contain only two metals?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
7 0
<span>No. Aluminum has more than two.</span>
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Which of these describes the role of gelada baboons in their ecosystem?
katen-ka-za [31]

Answer:

Gelada baboons plays a significant role.

Explanation:

The role of gelada baboons in their ecosystem is very important because they aerate the soil for plants which is necessary for good plant growth. These gelada baboons also helps in controlling the population of predator in their ecosystem which is very essential for the stability and equilibrium of the ecosystem so gelada baboons has a good effect on both plants and animals in their ecosystem.

6 0
3 years ago
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the frequency of a given region of the electromagnetic spectrum is more than 3 x 10^19HZ. note that the speed of light is 2.998
Cerrena [4.2K]
<span>To solve this problem, You need to look up a picture/diagram of the electromagnetic spectrum. This will have the wave regions listed as well</span> as frequencies and wavelength.
Wavelength is distance/length of one wave, which can be calculated using frequency (hz = s^-1) and the speed of light.
2.998 x 10^8 m/s ÷ 3 x 10^19 s^-1 = 9.99 x 10^-12 m

The Frequency given falls in between X-rays and Gamma rays. The wavelength however; is in the Gama ray region.




5 0
3 years ago
Read 2 more answers
About 6 × 109 g of gold is thought to be dissolved in the oceans of the world. If the total volume of the oceans is 1.5 × 1021 L
Lelechka [254]

First, determine the number of moles of gold.

Number of moles  = \frac{given mass in g}{molar mass}

Given mass of gold  =6 \times 10^{9} g

Molar mass of gold  = 196.97 g/mol

Put the values,

Number of moles of gold  = \frac{6 \times 10^{9} g}{196.97 g/mol}

= 0.03046\times  10^{9} mole or 3.046\times  10^{7} moles

Now, molarity  = \frac{moles of solute}{volume of the solution in liters}

Put the values, volume of ocean  =1.5 \times 10^{21} L

Molarity = \frac{3.046\times 10^{7} moles}{1.5 \times 10^{21} L}

= 2.03\times 10^{-14} M

Thus, average molar concentration = 2.03\times 10^{-14} M




6 0
3 years ago
What mass of F2 is needed to produce 180 g of PF3 if the reaction has a 78.1% yield?
nexus9112 [7]

Answer:

91.26 g

Explanation:

Given data:

Mass of PF₃ = 180 g

Mass of F₂ required = ?

Solution:

Chemical equation:

P₄ + 6F₂   → 4PF₃

Moles of PF₃:

Number of moles = mass/ molar mass

Number of moles = 180 g/ 88 g/mol

Number of moles = 2.05 mol

Now we will compare the moles of PF₃ with F₂.

                        PF₃            :           F₂

                          4               :           6

                          2.05         :           6/4×2.05 = 3.075

Mass of  F₂:

Mass of F₂ = moles × molar mass

Mass of F₂ = 3.075 mol × 38 g/mol

Mass of F₂ =  116.85 g

If reaction yield is 78.1%:

116.85 /100 ×78.1 = 91.26 g

6 0
3 years ago
This is an riddle.
Lostsunrise [7]

Answer: The answer is Iceberg

7 0
3 years ago
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