Speed of ball is 19.80 m/s .
<u>Explanation:</u>
We have , a 2.0 kg ball is resting at the top of a 20 m hill. if the ball rolls down the entire hill,We need to find how fast will it be going.Let's find out:
We know that,
Potential energy : This is the energy possessed by an object due to it's virtue of height and is given by , where m is mass , g is acceleration due to gravity & h is height !
Kinetic energy : This is the energy possessed by an object due to it's virtue of motion and is given by , where m is mass & v is the velocity of object !
By conservation of energy :
⇒
⇒
⇒
According to question , h=20 m i.e.
⇒
⇒
⇒
Hence , Speed of ball is 19.80 m/s .
Answer:
Fg = 98.1 [N]; N = 98.1 [N]; Ff = 39.24 [N]; a = 2.076[m/^2]
Explanation:
To solve this problem, we must make a free body diagram and interpret each of the forces acting on the box. In the attached diagram we can find the free body diagram.
The gravitational force is equal to:
Fg = (10 * 9.81) = 98.1 [N]
Now by summing forces on the Y axis equal to zero, we can find the normal force exerted by the surface.
N - Fg = 0
N = Fg
N = 98.1 [N]
The friction force is defined as the product of normal force by the coefficient of friction.
Ff = N * μ
Ff = 98.1 * 0.4
Ff = 39.24 [N]
By the sum forces on the x-axis equal to the product of mass by acceleration (newton's second law), we can find the value of acceleration.
60 - Ff = m * a
60 - 39.24 = 10 * a
a = 2.076[m/^2]
Answer:
440J
Explanation:
First, let us find the <u>weight </u>of the barbell.
The formula to find the weight is :
W = m × g
Here,
m ⇒ mass ⇒ 20 kg
g ⇒ acceleration of gravity
<u>Let us find it now.</u>
W = m × g
W = 20 kg × 10 ms⁻²
W = 200N
And now let us find<u> the work done by this weight lifter.</u>
Work = Force × Displacement
<u>Let us find it now.</u>
Work = Force × Displacement
= 200N × 2.2m
=<u> 440J</u>
Answer:
Explanation:
We are asked to find the acceleration of a box.
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the box is 5 kilograms. There are two forces applied: a 25 Newton force and a 50 Newton force, both applied right. Since they are applied in the same direction, we can add them.
- 25 N right + 50 N right = 75 N right.
Now we know 2 of the variables in the formula:
- F= 75 N or 75 kg*m/s²
- m= 5 kg
Substitute the values into the formula.
We are solving for a, so we must isolate the variable. It is being multiplied by 5 kilograms. The inverse operation of multiplication is division. Divide both sides by 5 kg.
The units of kilograms cancel.
The acceleration is in the same direction as the force, so the acceleration is <u> 15 meters per second squared to the right.</u>
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