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ELEN [110]
3 years ago
11

A compound consisting of atoms of small atomic mass is more likely to require

Physics
1 answer:
MArishka [77]3 years ago
4 0
A lower temp to liquefy

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Tim jogs a distance of 7.2 km to the west. Then he turns south and jogs 1.4 km. West is the resultant if Tim's jog back to the b
vesna_86 [32]

Answer:

Explanation:

If Tim jogs a distance of 7.2 km to the west and then he turns south and jogs 1.4 km, the resultant displacement of Tim is calculated using the pythagoras theorem as shown;

R² = 7.2²+1.4²

R² = 51.84+1.96

R² = 53.8

R = √53.8

R = 7.33 km

Hence  the resultant of Tim's jog back to the beginning is 7.33km

3 0
4 years ago
A high intake of alcohol and sugar has little to no real affect on the triglycerides prouction
docker41 [41]
False) high intake of alcohol and sugar increases the triglycerides.
8 0
3 years ago
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a batte
VikaD [51]

Answer:

R_3 < R_1 < R_2

Explanation:

The resistance of a wire is given by:

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

1) The first wire has length L and cross-sectional area A. So, its resistance is:

R_1=\frac{\rho L}{A}

2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is

R_2=\frac{2\rho L}{A}

3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is

R_3=\frac{\rho L}{2A}

By comparing the three expressions, we find

R_3 < R_1 < R_2

So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).

5 0
3 years ago
Prove that s=ut+½at²​
katrin2010 [14]

Explanation:

Distance travelled = Area under the line

= ut + ½ (v-u)t

Acceleration (a) = (v-u)/t and so (v-u) = at

Therefore,

Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²

Thus,proved.

3 0
3 years ago
Three resistors are connected in series to a 42.1 V battery: R1 = 2.96 Ω, R2 = 7.48 Ω and R3 = 7.42 Ω. Now, as R3 heats up, its
LuckyWell [14K]

Answer:

dP/dt = 26.12 W/s

Explanation:

First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:

dR₃/dt = 0.552 Ω/s

where,

dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω

dt = time interval = ?

Therefore,

84.28 Ω = (0.552 Ω/s)(dt)

dt = (84.28 Ω)/(0.552 Ω/s)

dt = 152.68 s

Now, we find change in power (dP):

dP = V(R₁ + R₂ + dR₃)

dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)

dP = 3987.71 W

Dividing by dt:

dP/dt = 3987.71 W/152.68 s

<u>dP/dt = 26.12 W/s</u>

7 0
3 years ago
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