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Phoenix [80]
3 years ago
5

What is a situation in which friction is helpful?

Physics
1 answer:
bagirrra123 [75]3 years ago
8 0
When driving a car on the road
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What is the CGS unit of current?
tangare [24]

The answer you are looking for is biot.

6 0
3 years ago
Read 2 more answers
Type your answers to these 4 questions in the submission area.
ELEN [110]
1)the edges where two plates meet are plate boundaries.

2)a sudden slip on a fault triggers an earthquake as stress in the edge overcomes the tension that releases energy into waves that move through the surface of the earth and cause a shake.

3)motion of the ground, aftershocks, shuddering, trembling, wobbling, crashing, falling, breaking, and more

4) the outer layer of Earth is the crust (lithosphere) which is made up of hot molten rock and granite.
4 0
3 years ago
a particle of mass 1.3kg is sliding down a frictionless slope inclined at 30 to the horizontal. the acceleration of the particle
OverLord2011 [107]

Answer:

4.9\ m/sec^2

Explanation:

The computation of acceleration of the particle down the slope is shown below:-

data provided in the question

Particle of mass = 1.3 kg i,e sliding down

Inclined = 30 to the horizontal

based on the above information

Force is given by

N = mg\ cos \theta ............ 1

and sliding force is given by

F = mg\ sin\alpha

a = g(sin\ 30^{\circ})

= 9.8\times \frac{1}{2} m/sec^2

= = 4.9\ m/sec^2

Hence, the acceleration of the particle down the slope is 4.9 m/sec^2

4 0
3 years ago
A brass statue with a mass of 0.40 kg and a density of 8.00×103kg/m3 is suspended from a string. When the statue is completely s
Mars2501 [29]

Answer:

ρ = 1469  kg/m³

Explanation:

given,

mass of statue = 0.4 Kg

density of statue = 8 x 10³ kg/m³

tension in the string = 3.2 N

density of the fluid = ?

Volume of the statue

V = \dfrac{0.4}{8\times 10^3}

V = 5 x 10⁻⁵ m³

W = ρ g V

W = ρ x 9.8 x 5 x 10⁻⁵

now, tension on the string will be equal to

T = mg - W

3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵

ρ x 9.8 x 5 x 10⁻⁵ = 0.72

ρ = 1469  kg/m³

8 0
3 years ago
What is watt equivalent to in terms of kg,m and s
daser333 [38]

F=ma=kg*m/s^2=N

Work=W=Force*d=N*m

P=W/time=N*m/s=kg*m^2/s^3=kg*m^2*s^-3=Watt

So 1 Watt of Power is equivalent to (kg*m^2)/s^3 or kg*m^2*s^-3


Any questions please feel free to ask. Thank you

3 0
3 years ago
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