Answer: electronegativity
Explanation:
Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.
The size of an atom decreases as we move across the period because the electrons get added to the same shell and the nuclear charge keeps on increasing. Thus the electrons get more tightly held by the nucleus.
As, the size of an element decreases, the valence electrons come near to the nucleus. So, the attraction between the nucleus and the shared pair of electrons increases and thus the electronegativity increases.
Answer:
Punctuated sedimentation
Explanation:
Punctuated sedimentation isn't part of the molecular homologies or the theory of molecules
Answer:
aaksj
Explanation:
a) the capacitance is given of a plate capacitor is given by:
C = \epsilon_0*(A/d)
Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:
The plates are squares so their area is given by:
A = L^2 = 0.19^2 = 0.0361 m^2
C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F
b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:
Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C
c) The electric field on a capacitor is given by:
E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]
E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m
d) The energy stored on the capacitor is given by:
W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J
The horizontal component of speed remains constant at 10 m/s.
After 1 s, a vertical component of speed = gt = 9.8(1) = 9.8 m/s is added to the horizontal speed.
The size of the total speed of the ball after 1 s = √(10²+9.8²) = √196.04 ≈ 14.0 m/s <=
You are correct.
Answer:
d) the total resistance is 4 + 5 = 9 ( ohm)
e) the current in the circuit is 18/9 = 2(A)
f) the voltage in R = 4 ohm is 2.4 = 8 (V)
the voltage in R = 5 ohm is 18 - 8 = 10 (V)
