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MArishka [77]
3 years ago
8

Why is it difficult to develop a policy for the disposal of spent fuel rods? (1 point)

Physics
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

The rods remain radioactive for thousands of years, so storage is a difficult problem.

Explanation:

Fuel rods represents the main element of the reactor core of a nuclear power plant.

They contain uranium-238 (U-238) enriched with uranium-235 (U-235), which is very unstable; when the nuclei of uranium absorb slow neutrons, they undergo nuclear fission, breaking apart and releasing huge amounts of energy.

In the process, several neutrons are released alongside with other products, and when they are slown down, they can be absorbed by other nuclei of uranium, further inducing more fissions.

The half-life of U-238 is 4.5 billion years, while the half-life of U-235 is approx. 700 million years: this means that the fuel rods remain highly radioactive for a very long time. Therefore, it is necessary to properly dispose them in a safe place where they do not represent a hazard. For instance, fuel rods: for example, they can be placed in sealed containers (built using concrete/steel to shield from the radiation) and buried underground.

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Oil and gas were formed millions of years ago from what
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3 years ago
is this true or false? an object with a mass of 9.0kg has an acceleration of 3m/s2. the force acting on it is 3N
ludmilkaskok [199]

The answer is "False". The force acting on the object is 27 N.

According to Newton's second law, when a force <em>F</em> acts on am object of mass <em>m</em>, it produces an acceleration <em>a</em>. The force is given by the expression,

F=ma

Thus, if the body has a mass of 9.0 kg and if it has an acceleration of 3 m/s², then, on substituting the values in the equation for force,

F=ma\\ =(9.0kg)(3m/s^2)\\ =27N

Thus, it can be seen that the force acting on the body is 27 N and not 3 N as is mentioned in the statement. Hence the statement is false.

5 0
3 years ago
If the distance from a light source triples, how does light intensity change? The intensity will be 3x greater. The intensity wi
Tcecarenko [31]

Answer:

The intensity will be 1/9 as much.

Explanation:

The intensity of the light or any source is inversely related to the square of the distance.

I\alpha \frac{1}{r^{2} }

Now according to the question the distance is increased by three times than,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{r_{2}^{2} }

Therefore,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{(3r_{1})^{2} }\\\frac{I_{2} }{I_{1} }=\frac{1}{9} \\{I_{2}=\frac{1}{9}{I_{1} }

Therefore the intensity will become 1/9 times to the initial intensity.

3 0
3 years ago
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