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3 years ago

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If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 11

grams of X to form the same compound? grams

1 answer:

kykrilka [37]3 years ago

3 0

This is sort of simple. 2 grams of X can combine with 4 grams of Y to form XY. Y is 2 times the amount of grams in X. So if there are 11 grams of X there are 22 grams of Y to form XY. Or you could take 11 divided by 2 is 5.5 and then multiply 4 by 5.5 to get 22. If this is wrong please tell me I would be very happy to know.

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zhenek [66]

115 divided by 2 equals 57.5

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A light wave travels through space at a speed of 3 x 108 m/s. If the wavelength of some light wave is 2 x10-3 m, what is the fre

kifflom [539]

Here is your answer

b) $\huge 1.5× {10}^{11} Hz$

REASON :

We know that

Velocity= Frequency× Wavelength

So,

Frequency= Velocity/wavelength

Here,

V= 3× 10^8 m/s

Wavelength= 2×10^-3 m

Hence,

Frequency= 3×10^8/2×10^-3

= 3/2 × 10^11

= 1.5× 10^11 Hz

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3 years ago

A 1056-hertz tuning fork is struck at the same time as a note on the piano and you hear 2 beats/second. You tighten the piano st

elena-14-01-66 [18.8K]

Answer:

The frequency of the piano string is <em>1059 Hz</em>.

Explanation:

The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.

As the piano string gets tightened, the frequency beat becomes 3 beats/second.

Therefore,

fb = $fb = fpiano - ftuning fork\\ 3 Hz=fpiano-1056Hz\\ fpiano=1056Hz+3Hz\\ fpiano=1059Hz$

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3 years ago

A speed-time graph is shown below:

VladimirAG [237]

Answer: $0.5 m/s^{2}$

Explanation:

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$a_{ave}=\frac{\Delta V}{\Delta t}}$

Where:

$\Delta V=V_{f}-V_{o}$ being $V_{o}=0 cm/s$ the initial velocity and $V_{f}=4 cm/s$ the final velocity (according to the information given from the described graph)

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Then:

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3 years ago

A cube of water 10 cm on a side is placed in a microwave beam having Ea = 11 kV/m‘ The microwaves illuminate one faceofthe cube,

Shtirlitz [24]

Answer:

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

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We need to calculate the rate of energy transfer from the beam to the cube

Using formula of rate of energy

$P=(0.80)IA$

$P=0.80\times\dfrac{c\mu_{0}E^2}{2}\times A$

Put the value into the formula

$P=0.80\times\dfrac{3\times10^{8}\times8.85\times10^{-12}\times(1.1\times10^{4})^2}{2}\times(10\times10^{-2})^2$

$P=1285.02\ W$

We need to calculate the amount of heat

Using formula of heat

$E =mc\Delta T$

$E =\rho Vc\Delta T$

Put the value into the formula

$E=1000\times(0.10)^3\times4186\times41$

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Using formula of time

$t=\dfrac{E}{P}$

Put the value into the formula

$t=\dfrac{171626}{1285.02}$

$t=133.5\ sec$

Hence, The time is 133.5 sec.

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3 years ago