<span>The pressure will increase because the force of the collisions between the gas particles and the walls of the container will increase. </span>
Answer:
When a Magnesium Ribbon is burnt, a powdery substance called magnesium oxide is formed.
Explanation:
There has obviously been a chemical change because several chemical properties of the magnesium have been modified: the color, the texture and the mass.
The increase in mass is due to the fact that oxygen from the air has combined with the magnesium to make magnesium oxide, MgO.
The chemical equation, Mg + O2 MgO shows this reaction but it needs to be balanced to make 2Mg + O2 2MgO.
Using stoichiometry, we can convert this eqation into an equation with moles:
2 mol Mg + 1 mol O2 2 mol MgO.
Next, we convert to grams using atomic masses obtained from the periodic table:
48g Mg + 32g O2 80g MgO
Lastly, we determine the same thing in the proportions we used. In other words, we used only 0.15g of Mg (not 48g) so everything needs to be divided by 320. So 80 / 320 = 0.25 g. If we burn 0.15 g of Mg, we obtain 0.25 g of MgO.
Hope this helps!!!
This is my first answer.
<h2>
Hello!</h2>
The answer is:
The new volume is 2.84 L.

<h2>
Why?</h2>
To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.
Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.
The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.
The law is defined by the following equation:

Where,
is the first pressure.
is the first volume.
is the first temperature.
is the second pressure.
is the second volume.
is the second temperature.
So, we are given the following information:

Then, isolating the new volume, and substituting, we have:

Hence, the new volume is 2.84 L.

Have a nice day!
Answer:
The mass of the acetic acid is 13.5 g
Explanation:
Given;
weight percent of the acetic acid (ratio of solute to total solution), w/w = 98 %
volume of acetic acid, v = 12.83 mL
density of acetic acid, ρ = 1.05 g/mL
density is given by;
density = mass / volume
mass = density x volume
mass of the acetic acid in 12.83 mL = 1.05 g/mL x 12.83 mL
mass of the acetic acid in 12.83 mL = 13.5 g
Therefore, the mass of the acetic acid is 13.5 g