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3 years ago

Question 2 (1 point)

1 answer:

7 0

To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.

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A rectangular fence is 3 times as long as it is wide. The perimeter is 60ft. Find the dimensions of the fence

Mashutka [201]

Answer:

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

Explanation:

To solve this problem we will turn this question into an equation.

The equation for the perimeter of a rectangle is 2l + 2w = perimeter.

In the question we were given the perimeter so we can go ahead and plug this in.

2l + 2w = 60

In the question we are also told that the fence is 3 times as long as it is wide. This means that 1l = 3w. We can now subsitute l for 3w so that we only have one variable.

2(3w) + 2w = 60

Now we can simply use algebra to solve for w.

6w + 2w = 60

8w = 60

w = 7.5

Now that we know the value of w we can find the value of l since we know 1l = 3w.

l = 3w

l = 3(7.5)

l = 22.5

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

7 0

3 years ago

What type of subatomic particles are found in the cloud?

Novay_Z [31]

Answer:

Electrons are particles that surround the nucleus of an atom like a cloud. As with protons and neutrons, electrons are essential to an atom's structure.

8 0

3 years ago

Can anybody check my answer?

anzhelika [568]

Answer:

$\boxed{\text{25. 20 L; 26. 49 K}}$

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}$

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 × 8.314 × T

2026 = 41.57T

$T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}$

6 0

3 years ago

Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M

Andrej [43]

The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-<span>1.3*10^-2]=0.0188. The final answer is Kc=0.0188.</span>

6 0

3 years ago

You have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g

Leno4ka [110]

If you were to cut the radium in half and have only 90 g, it will take up 18 cm³.

<h3>What is density?</h3>

The density of an object is the ratio of mass to volume of object.

Density = mass/volume

volume = mass/density

at a constant density, the volume of an object is proportional to its mass.

From the question, you have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g, the new mass will take the following volume.

180 g = 36 cm³

90 g = ?

= (90 x 36) / 180

= 18 cm³

Thus, if you were to cut the radium in half and have only 90 g, it will take up 18 cm³.

Learn more about radium here: brainly.com/question/23781489

#SPJ1

6 0

1 year ago