The anwer roght here is the last one d. 0.0556 mol. The next procedure says why this is right:
<span>3.35 x 10^22 atoms x (1 mol / 6.02 x 10^23 atoms) = 0.0556 mol
</span>
I hope this can help you greatly
Answer:
5. Please Kemi, be careful not to place your feet on the lava flowing down from the mountain.
6. A Ore canbe defined as a natural solid material gotten from the earth, which a metal or valuable mineral can be extracted from.
7. Diamond.
8. Fracture
9. Molten Magma
10. Natural
11. In-organic
12. Solid
13. Crystal structures
14. Definite Chemical Composition
15. Metallic
16. Non-Metallic
17. Energy Minerals
Explanation:
Answer:
![Kc=\frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D)
Explanation:
Let's consider the following reaction.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The equilibrium constant (Kc) is <em>the products of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.</em>
![Kc=\frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D)
If you wanted to calculate [CH₃OH], suppose that the molar concentrations for CO and H₂ at equilibrium are [CO] = 0.04 M and [H₂] = 0.08 M. The concentration of methanol at equilibrium is:
![Kc= 2.3 \times 10^{4} = \frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} } =\frac{[CH_{3}OH]}{(0.04).(0.08)^{2} }\\ \ [CH_{3}OH]=5.9M](https://tex.z-dn.net/?f=Kc%3D%202.3%20%5Ctimes%2010%5E%7B4%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%280.04%29.%280.08%29%5E%7B2%7D%20%7D%5C%5C%20%5C%20%5BCH_%7B3%7DOH%5D%3D5.9M)
Mode is the most common value in the set. I remember learning a song and it was “hey diddle diddle, the medians the middle you add then divide for the mean mode is the one that you see the most and the range is the difference between”