The increase in the boiling point of a solvent is a colligative property.
That means that the increase in the boling point will be related to the number of particles (molecules or ions) present in the solution.
The higher the number of particles (molecules or ions) the higher the increase in the boiling point.
All the aqueous solutions presented are electrolytes, i.e. the solutes are ionic compounds.
Then, you have to compare the number of ions that you have in each solution.
A) 1.0 M KCl ---> 1.0 M K+ + 1.0 MCl- = 2 moles of particles / liter
B) 1.0 M CaCl2 --> 1.0M Ca(2+) + 1.0M * 2 Cl (-) = 3 moles of particle / liter
C) 2.0M KCl ---> 2.0 M K+ + 2.0 M Cl- = 4 moles of particle / liter
D) 2.0 M CaCl2 ----> 2.0 M Ca (2+) + 2.0M * 2 Cl (-) = 6 moles of particle / liter.
Then, the solution 2.0M CaCl2(aq) has the highest increase in the boiling point.
Answer: option D) 2.0 M Ca Cl2(aq)
Answer:
The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g
Explanation:
We do this by preparing the equation:
Mass = concentration (mol/L) x volume (L) x Molar mass
Mass = 1.0 M x 2.5 L x 40 g/mol
Mass = 100 g
Answer:
P = 83.16 Watt
Explanation:
Given data:
Mass of box = 2 Kg
velocity of box = 29.7 m/s
Time = 21 sec
Power = ?
Solution:
Formula:
Power = work done/time
Now we will calculate the work done.
W = force × distance ...... (1)
d = speed /time
d = 29.7 m/s× 21 s
d = 623.7 m
Force:
acceleration = 29.7 m/s / 21 s
a = 1.4 m/s²
Force = m×a
Force = 2 kg×1.4 m/s²
Force = 2.8 N
Now we will put the values in equation 1.
W = F × d
W = 2.8 N ×623.7 m
W = 1746.36 Nm
Now for power:
P = W / time
P = 1746 Nm / 21 s
P = 83.16 Watt
