Skeletal structure is missing, so i have attached it.
Answer:
Option B: Omega 6 fatty acid
Explanation:
Arachidonic Acid is defined as an essential and unsaturated fatty acid. It's usually found in animal and human fat including the liver, brain, and also glandular organs. While in animals, it is a constituent of their phosphatides.
Arachidonic Acid is formed as a result of the synthesis from dietary linoleic acid and it's a preliminary stage in the biosynthesis of prostaglandins, thromboxanes, and leukotrienes.
In short, Arachidonic acid is basically a long-chain fatty acid which is a C20, Omega 6 polyunsaturated fatty acid that has four Z-double bonds.
Mg+alcl3-->mgcl2+al is the
Answer:
6.61 × 10∧-29 m³
Explanation:
Given data:
Atomic radius= 143 pm = 143 × 10∧-12 m
volume = ?
Formula:
r = a/2√2
143 × 10∧-12 m = a/ 2√2
a= 143 × 10∧-12 m × 2√2
a= 404.4 × 10∧-12 m
where a is edge length, so we can calculate the volume by using following formula:
volume= a³
V= (404.4 × 10∧-12 m)³
v= 6.61 × 10∧-29 m³
Answer:
[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)
Explanation:
1. Molarity = moles solute / Volume solution in Liters
=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH
=> volume of solution (assuming density of final solution is 1.0g/ml) ...
volume solution = 9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution
Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH
2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)
From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln
= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.
If you are asking which is the most abundant, Uranium-238 is
