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sasho [114]
3 years ago
13

The anticodon is the three-base code on the tRNA molecule that binds to the codon on mRNA. What is the associated codon for the

anticodon CUA?
The anticodon is the three-base code on the tRNA molecule that binds to the codon on mRNA. What is the associated codon for the anticodon CUG? 
Chemistry
2 answers:
Oksi-84 [34.3K]3 years ago
8 0
So it would be the complimentary base pairing, meaning that the codon must have been:
GAC
(Which is the codon for aspartic acid)
hjlf3 years ago
6 0
It would be GAT for the first one and GAC for the second.
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Question 2(Multiple Choice Worth 3 points)
viktelen [127]

Answer:

2.0 x 10⁻³ M/s.

Explanation:

  • The rate of the reaction is the change of the concentration of the reactants or the products with time.

<em>The rate of the reaction = - Δ[reactants]/Δt = - [(0.6 M - 1.8 M)]/(580 s - 0 s) = 2.069 x 10⁻³ M/s.</em>

5 0
3 years ago
What does diatomic mean?
Tanya [424]
Answer:  [A]:  "<span><span>two atoms, both the same element, bonded together</span>".
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4 0
4 years ago
A weather balloon calibrated at 0.00 °C to
Natasha2012 [34]

Answer:

17.3 L

Explanation:

With all other variables held constant, you can find the missing volume using the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before we can solve, we need to convert Celsius to Kelvin (because we don't want negative numbers or temp. of 0).

V₁ = 20.0 L                                            V₂ = ? L

T₁ = 0.00 °C + 273.15 = 273.15 K         T₂ = -36.2 °C + 273.15 = 236.95 K

V₁ / T₁ = V₂ / T₂                                             <----- Charles' Law equation

20.0 L / 273.15 K = V₂ / 236.95 K               <----- Insert values

0.0732 = V₂ / 236.95 K                               <----- Simplify left side

17.3 L = V₂                                                   <----- Multiply both sides by 236.95

6 0
2 years ago
Treatment of 2,4,6-tri-tert-butylphenol with bromine in cold acetic acid gives the compound C18H29BrO in quantitative yield. The
Cloud [144]

Answer:

2,4,6-tri-tert-butylcyclohexa-2,5-dienone

Explanation:

1. Information from the formulas

C₁₈H₃₀O ⟶ C₁₈H₂₉BrO

A Br has replaced an H.

2. Information from the reaction

These look like the conditions for an electrophilic aromatic substitution.

3. Possible mechanism (Fig. 1)

The product must be highly symmetrical, because there are so few NMR signals.

(i) The bromonium ion attacks at the para position, forming a resonance-stabilized carbocation intermediate.

(ii) A bromide ion attacks the H of the hydroxyl group to form 2,4,6-tri-tert-butylcyclohexa-2,5-dienone.

4. Confirmatory evidence (Fig. 2)

(a) Infrared  

1630 cm⁻¹:  C=O stretch

1655 cm⁻¹ : C=C stretch

(b)NMR

1.2 (9h, s):    the 4-tert-butyl group

1.3 (18H, s): the 2- and 6- tert- butyl groups

6.9 (2H, s):    the alkene H atoms

The ratio is 9:18:2.

3 0
3 years ago
Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?
Llana [10]
Move the decimal point over to the left 2 spaces and mult by the number of ml .
473 ml times 0.70 = 331.1 ml
6 0
3 years ago
Read 2 more answers
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