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solniwko [45]
1 year ago
10

two wires have the same length, but the second has twice the diameter of the first. find the resistance of the second wire if th

e resistance of the first is 4ω.
Physics
1 answer:
djverab [1.8K]1 year ago
5 0

2ω is the resistance of the second wire if the resistance of the first is 4ω if two wires have the same length, but the second has twice the diameter of the first.

R= 4ω.

R = ρl/A

2d=r

R2=2ω

Resistance is the capacity of a conductor to obstruct the passage of an electric current through it. It is controlled by the interaction of the applied voltage and the electric current passing through it.

Conductors have very little resistance, whereas insulators have a significant amount of resistance. The resistance increases as the current flow decreases. Resistance is influenced by the properties and dimensions of the material (area of cross section)

To know more about  resistance visit : brainly.com/question/14547003

#SPJ4

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The given magnitude of forces of F₁ = F₄, F₂ = F₃, F₁ = 2·F₂, give the

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The given parameters are;

F₁ = F₄

F₂ = F₃

F₁ = 2·F₂

Therefore;

F₄ = 2·F₂

In vector form, we have;

\vec{F_4} = \mathbf{\frac{\sqrt{3} }{2} \cdot F_4 \cdot \hat i -  0.5 \cdot F_4 \hat j}

\vec{F_2} = \mathbf{ -F_2 \,  \hat j}

Clockwise moment due to F₄, M₁ = -0.5 \times F_4 \,  \hat j  \times \dfrac{R}{2}

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Given that the clockwise moment due to F₄ = The counterclockwise moment due to F₂, we have;

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Learn more about the resolution of vectors here:

brainly.com/question/1858958

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