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3 years ago

8

How are electrons distributed in the molecular orbitals, when the 1s orbitals of two hydrogen atoms combine to form a hydrogen m

olecule?

1 answer:

Evgesh-ka [11]3 years ago

3 0

Answer:

2 Electrons

Explanation:

Both the Hydrogen atom will share electron equally by covalent bonding. so there will be 2 electron in the bonding molecular orbital.

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Which is an example of a physical change?

levacccp [35]

Answer:

salt dissolving

Explanation:

hope it helps

5 0

3 years ago

Read 2 more answers

You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.

Bond [772]

Answer:

$d_t=266.918\ miles$ is the total distance of the trip travelled.

$s_{avg}=54.7895\ mph$ is the average speed of the journey

Explanation:

Given:

duration of first interval, $t_1=3.22\ hr$

speed during the first interval, $v_1=65.9\ mph$

duration of stoppage, $t_0=42.1\ min=0.7017\ hr$

duration of second interval, $t_2=0.95\ hr$

speed during second interval, $v_2=57.6\ mph$

<u>Now the total distance travelled:</u>

$\rm distance=speed\times time$

$d_t=v_2.t_2+v_1.t_1$

$d_t=57.6\times 0.95+65.9\times 3.22$

$d_t=266.918\ miles$

<u>The average speed:</u>

$\rm speed_{avg}=\frac{total\ distance}{total\ time\ taken}$

$s_{avg}=\frac{d_t}{(t_0+t_1+t_2)}$

$s_{avg}=\frac{266.918}{(0.7017+3.22+0.95)}$

$s_{avg}=54.7895\ mph$

4 0

4 years ago

A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the lef

stira [4]

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

$F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N$

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

4 0

3 years ago

A man pushes a box of 40kg up incline of 15°, if the man applies a horizontal force of 200N and the box moves up the plane a dis

Tatiana [17]

20 m is the correct answer

5 0

4 years ago

When placed 1.18 m apart, the force each exerts on the other is 11.2 N and is repulsive. What is the charge on each

aleksandr82 [10.1K]

Answer:

$q=41.62\ \mu C$

Explanation:

Given that,

Force between two objects, F = 11.2 N

Distance between objects, d = 1.18 m

We need to find the charge on each objects. The force between charges is as follows :

$F=\dfrac{kq^2}{r^2}\\\\q=\sqrt{\dfrac{Fr^2}{k}} \\\\q=\sqrt{\dfrac{11.2\times (1.18)^2}{9\times 10^9}} \\\\q=41.62\ \mu C$

So, the charge on each sphere is $41.62\ \mu C$ .

7 0

3 years ago