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Kruka [31]
2 years ago
8

What is the mass of 15100 mL of oxygen gas at STP?

Chemistry
1 answer:
adell [148]2 years ago
5 0

Answer:

02 has a mass of 1.78 g.

Explanation:

hope this helps

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If a substance is soluble it will <br> A. sink.<br> B. dissolve.<br> C. shrink.
svetlana [45]
B)dissolve is the answer
3 0
3 years ago
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Why polythene bags create big problem in garbage disposal ?
Mariana [72]

Answer:

Polythene bags are so lightweight and aerodynamic, they are easily picked up and carried by the wind. They can escape from trash bins, recycle bins, garbage trucks, and landfills, and end up littering the landscape.

hope it helps

Explanation:

3 0
4 years ago
Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of
Serhud [2]

Answer:  0.17 m CH_3COONH_4 : Highest freezing point

0.20 m CoSO_4: Second lowest freezing point

0.18 m MnSO_4: Third lowest freezing point

0.42 m ethylene glycol: Lowest freezing point

Explanation:

Depression in freezing point  is a colligative property which depend upon the amount of the solute.

\Delta T_f=i\times k_f\times m

where,

\Delta T_f = change in freezing point

i= vant hoff factor

k_f = freezing point constant

m = molality

a) 0.17 m CH_3COONH_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for CH_3COONH_4, thus total concentration will be 0.34 m

b) 0.18 m MnSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for MnSO_4, thus total concentration will be 0.36 m

c) 0.20 m CoSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for CoSO_4, thus total concentration will be 0.40 m

d) 0.42 m ethylene glycol

For non electrolytes undergoing no dissociation, vant hoff factor is equal to 1 . Thus i = 1 for ethylene glycol, thus concentration will be 0.42 m

The more is the concentration, the highest will be depression in freezing point and thus lowest will be freezing point.

4 0
3 years ago
Explain why the chemical formula for calcium hydroxide , Ca(OH)2 is not written as CaO2H2
makvit [3.9K]
The formula CaO₂H₂ correctly gives the relative number of each type of atom in the compound.
But the OH group usually behaves as a unit. It doesn't fall apart.
So chemists have agreed to write the OH group as a unit: Ca(OH)₂.
This shows that there are 1 Ca atom and 2 OH groups in a formula unit of calcium hydroxide.
5 0
4 years ago
Read 2 more answers
What is the oxidation state for a Mn atom?<br> (1) 0 (2) +7 (3) +3 (4) +4
ss7ja [257]

Answer : The correct option is, (1) 0

Explanation :

Oxidation state or oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with sign (+ and -) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

As per question, 'Mn' atom is a free element that means it is present in their elemental state then the oxidation state will be zero.

Hence, the correct option is, (1) 0

5 0
3 years ago
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