Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T
1 answer:
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The energy that will be released will be 8.95×10^(21) Joules
for comparison, the Nagasaki atom bomb released 8.8*10^(13) Joules
so this meteorite is (8.95×10^(21))/(8.8*10^(13))=100×10^6 (100 million) times more destructive
for comparison, the Nagasaki atom bomb released 8.8*10^(13) Joules
so this meteorite is (8.95×10^(21))/(8.8*10^(13))=100×10^6 (100 million) times more destructive
Answer:
Part a: <em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>
Part b: <em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>
Part c: <em>The value of Young's modulus at given point is 172 GPa.</em>
Part d: <em>The percentage elongation is 18.55%.</em>
Part e: The percentage reduction in area is 15.81%
Explanation:
From the complete question the data is provided for various Loads in ductile testing machine for a sample of d0=20 mm and l0=40mm. The plot is drawn between stress and strain whose values are calculated using following formulae. The corresponding values are attached with the solution.
The engineering-stress is given as
Here F are different values of the load
Now Strain is given as
So the curve is plotted and is attached.
<h2>Part a</h2><em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>
<h2>Part b</h2><em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>
<h2>Part c</h2>Young's Modulus is given as
<em>The value of Young's modulus at given point is 172 GPa.</em>
<h2>Part d</h2>The percentage elongation is given as
So the percentage elongation is 18.55%
<h2>Part e</h2>The reduction in area is given as
So the reduction in area is 15.81%
