Answer:
<u>Option 1</u>
Explanation:
As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :
- <u>Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.</u>
Answer:
The highest grade level is college.
Answer:
the final temperature would have been 2.81 °C if the pressure drop was 2 psi
Explanation:
if we assume that is no change in volume, there are not leaks present and also that the gas inside the football behaves as an ideal gas, we have:
initial state) P1 V = n R T1
final state) P2 V = n R T2
where P = absolute pressure , V = volume occupied by the gas, n = number of moles of gas, R = ideal gas constant T= absolute temperature
therefore since V= constant (constant volume) and n= constant ( no leaks), if we divide both equations
P2/P1 = T2/T1
therefore
T2 = T1 *(P2/P1)
since P1 absolute = P1 relative + P atmospheric (14.7 psi) = 12.5 psi + 14.7 psi = 27.2 psia
also P2 = P1 - 2 psi = 25.2 psia
T1 = 24.7°C + 273 °C = 297.7 K
therefore
T2 = T1 * (P2/P1) = 297.7 K ( 25.2 psia/27.2 psia) = 275.81 K
thus T2 = 275.81 K = 2.81 °C
Answer:
Can you write it in English plz
Explanation: